Pygame(十)作业

Pygame(十)作业

作业详解

第一题

题目

随心圆:以鼠标左键点击为圆心,画一个半径50 ,颜色随机的圆

分析

需求分析:

1. 鼠标左键点事件
2. 获取鼠标的位置
3. 颜色随机
4. 画圆

代码

1. 鼠标左键点击事件
2. 获取鼠标的位置

if event.type == pygame.MOUSEBUTTONDOWN:
    if event.button == 1:
        pos = event.pos

3. 颜色随机

r = randint(0,255)
g = randint(0,255)
b = randint(0,255)
c = r, g, b

4.画圆

pygame.draw.circle(s, c, pos, 50,width = 1)

完整代码

方法一:

def homework1_1():
    pygame.init()
    s = pygame.display.set_mode((800, 600))

    while 1:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                sys.exit()
            if event.type == pygame.MOUSEBUTTONDOWN:
                if event.button == 1:
                    pos = event.pos
                    r = randint(0, 255)
                    g = randint(0, 255)
                    b = randint(0, 255)
                    c = r, g, b
                    s.fill((0, 0, 0))
                    pygame.draw.circle(s, c, pos, 50, width=1)
                    pygame.display.update()
        # 处理组合关闭游戏
        keys = pygame.key.get_pressed()
        if keys[pygame.LALT] or keys[pygame.K_RALT] and keys[pygame.K_F4]:
            sys.exit()

方法二:

def homework1_2():
    pygame.init()
    s = pygame.display.set_mode((800, 600))

    while 1:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                sys.exit()
        # 处理组合关闭游戏
        keys = pygame.key.get_pressed()
        if keys[pygame.LALT] or keys[pygame.K_RALT] and keys[pygame.K_F4]:
            sys.exit()

        # 处理鼠标事件
        mouse = pygame.mouse.get_pressed()  # 获取鼠标点击状态元组 三个元素分别代表左键 ,中键 ,右键的点击状态.点了就是True否则为False
        if mouse[0]:  # 判断左键有没有点击
            pos = pygame.mouse.get_pos()  # 点击了左键就获取鼠标的位置作为圆的圆心
            r = randint(0, 255)
            g = randint(0, 255)
            b = randint(0, 255)
            c = r, g, b
            s.fill((0, 0, 0))
            pygame.draw.circle(s, c, pos, 50, width=1)
            pygame.display.update()

与键盘的按键响应一样,鼠标的响应也可以用mouse模块来专门处理.这样会比用event事件直接处理来的简洁明了.

第二题

题目

点不中的矩形心:在屏幕中初始化一个矩形,当鼠标点击这个矩形时,矩形移动到鼠标没有点到的地方.
备注:判断一下点有没有在矩形内,可以用矩形的collidepoint(x,y) 当点(x,y)在矩形内时返回True,否则返回False

需求分析

1. 初始在屏幕中心画一个矩形形(大小没说,可以自定义)
2. 鼠标获取鼠标点击事件
3. 获取鼠标的位置
4. 判断位置是否在矩形内
5. 改变矩形的位置直到鼠标的位置不在矩形内为止

代码

1. 初始在屏幕中心画一个矩形

pygame.draw.rect(s, c, rect, width = 1)

2. 鼠标点击事件
3. 获取鼠标的位置

mouse = pygame.mouse.get_pressed()
if mouse[0]:
    pos = pygame.mouse.get_pos()

4. 判断位置是否在矩形内
5. 改变矩形的位置直到鼠标的位置不在矩形内为止

while rect.collidepoint(pos[0], pos[1]):
    rect.left = randint(0, 700)
    rect.top = randint(0, 500)

完整代码

def homework2():
    pygame.init()
    s = pygame.display.set_mode((800, 600))
    rect = pygame.Rect(350, 250, 100, 100)
    color = 0, 255, 0
    pygame.draw.rect(s, color, rect, width=1)
    pygame.display.update()
    while 1:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                sys.exit()
        mouse = pygame.mouse.get_pressed()  # 获取鼠标点击状态元组 三个元素分别代表左键 ,中键 ,右键的点击状态.点了就是True否则为False
        if mouse[0]:  # 判断左键有没有点击
            pos = pygame.mouse.get_pos()  # 点击了左键就获取鼠标的位置作为圆的圆心
            while rect.collidepoint(pos[0], pos[1]):
                rect.left = randint(0, 700)
                rect.top = randint(0, 500)
            s.fill((0, 0, 0))
            pygame.draw.rect(s, color, rect, width=1)
            pygame.display.update()
            
        # 处理组合关闭游戏
        keys = pygame.key.get_pressed()
        if keys[pygame.LALT] or keys[pygame.K_RALT] and keys[pygame.K_F4]:
            sys.exit()

第四题

题目

复制与粘贴:屏幕上初始一个矩形, 当鼠标框选中矩形时,按CTRL + C 复制 这个矩形,然后在鼠标下一次点击时以鼠标点击处为矩形的中心粘贴这个矩形

需求分析

代码

1. 屏幕上初始画一个矩形,大小颜色自定义

rect = pygame.Rect(350, 250, 100, 100)
color = 0, 255, 0
pygame.draw.rect(s, color, rect, width = 1)

2. 鼠标框选:

            if event.type == pygame.MOUSEBUTTONDOWN and not have_rect:
                if event.button == 1:
                    mouse_flag = True
                    start_pos = event.pos
            if event.type == pygame.MOUSEMOTION and mouse_flag:
                end_pos = event.pos
                left = start_pos[0] if start_pos[0] < end_pos[0] else end_pos[0]
                top = start_pos[1] if start_pos[1] < end_pos[1] else end_pos[1]
                width = abs(start_pos[0] - end_pos[0])
                height = abs(start_pos[1] - end_pos[1])
                new_rect = pygame.Rect(left, top, width, height)
                s.fill((0, 0, 0))
                pygame.draw.rect(s, color, rect, width=1)
                pygame.draw.rect(s, color, new_rect, width=1)
                pygame.display.update()

3. 判断框选的范围是不是把矩形整个包含进去了,如果包含了整个矩形,就复制一下这个矩形

            if event.type == pygame.MOUSEBUTTONUP and mouse_flag:
                if event.button == 1:
                    mouse_flag = False
                    if new_rect.contains(rect):
                        can_copy = True
                        s.fill((0, 0, 0))
                        pygame.draw.rect(s, (255, 0, 0), rect, width = 5)  # 框选成功加粗显示
                        pygame.display.update()

4. 复制

 keys = pygame.key.get_pressed()
            if keys[pygame.K_LCTRL] or keys[pygame.K_RCTRL] and keys[pygame.K_v] and can_copy:
                copy_rect = rect.move(0,0)
                print(copy_rect)
                can_copy = False
                have_rect = True

5.粘贴

            if event.type == pygame.MOUSEBUTTONDOWN and have_rect:
                if event.button == 1:
                    have_rect = False
                    pos = event.pos
                    copy_rect.center = pos
                    s.fill((0, 0, 0))
                    pygame.draw.rect(s, color, rect, width=1)
                    pygame.draw.rect(s, color, copy_rect, width=1)
                    pygame.display.update()

完整代码:

def homework4():
    pygame.init()
    s = pygame.display.set_mode((800, 600))
    rect = pygame.Rect(350, 250, 100, 100)
    color = 0, 255, 0
    pygame.draw.rect(s, color, rect, width=1)
    pygame.display.update()
    mouse_flag = False # 鼠标第一次点击的标识
    have_rect = False  # 有没有复制的标记
    can_copy = False  # 能不能复制的标记
    while 1:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                sys.exit()
            if event.type == pygame.MOUSEBUTTONDOWN and not have_rect:
                if event.button == 1:
                    mouse_flag = True
                    start_pos = event.pos
            if event.type == pygame.MOUSEMOTION and mouse_flag:
                end_pos = event.pos
                left = start_pos[0] if start_pos[0] < end_pos[0] else end_pos[0]
                top = start_pos[1] if start_pos[1] < end_pos[1] else end_pos[1]
                width = abs(start_pos[0] - end_pos[0])
                height = abs(start_pos[1] - end_pos[1])
                new_rect = pygame.Rect(left, top, width, height)
                s.fill((0, 0, 0))
                pygame.draw.rect(s, color, rect, width=1)
                pygame.draw.rect(s, color, new_rect, width=1)
                pygame.display.update()
            if event.type == pygame.MOUSEBUTTONUP and mouse_flag:
                if event.button == 1:
                    mouse_flag = False
                    if new_rect.contains(rect):
                        can_copy = True
                        s.fill((0, 0, 0))
                        pygame.draw.rect(s, (255, 0, 0), rect, width = 5)  # 框选成功加粗显示
                        pygame.display.update()
            keys = pygame.key.get_pressed()
            if keys[pygame.K_LCTRL] or keys[pygame.K_RCTRL] and keys[pygame.K_v] and can_copy:
                copy_rect = rect.move(0,0)
                print(copy_rect)
                can_copy = False
                have_rect = True
            if event.type == pygame.MOUSEBUTTONDOWN and have_rect:
                if event.button == 1:
                    have_rect = False
                    pos = event.pos
                    copy_rect.center = pos
                    s.fill((0, 0, 0))
                    pygame.draw.rect(s, color, rect, width=1)
                    pygame.draw.rect(s, color, copy_rect, width=1)
                    pygame.display.update()

        # 处理组合关闭游戏
        keys = pygame.key.get_pressed()
        if keys[pygame.K_LALT] or keys[pygame.K_RALT] and keys[pygame.K_F4]:
            sys.exit()