C语言实现扫雷游戏

要求：
1.第一次下子，不炸死。
2.坐标周围没雷，可以实现展开。
函数申明 ：gama.h

#ifndef _GAME_H_
#define _GAME_H_
#include
#include
#pragma warning(disable:4996)
#include
#include
#define ROWS 12
#define COLS 12
#define NUM 20 //雷数
void game();
void set_mine(char mine[ROWS][COLS], int row, int col, int *no_x, int *no_y);
void Show(char mine[ROWS][COLS], int row, int col);
int get_mine_count(char mine[ROWS][COLS], int x, int y);
#endif

主函数：main.c

#include "game.h"
void Menu()
{
	printf("##########################\n");
	printf("###1.play        2.exit###\n");
	printf("##########################\n");
	printf("## Please Enter select! ##\n");
}

int main()
{
	Menu();
	srand((unsigned int)time(NULL));
	int quit = 0;
	while (!quit)
	{
		int select = 0;
		printf("请输入你的选择：\n");
		scanf("%d", &select);
		switch (select)
		{
		case 1:
			game();
			break;
		case 2:
			quit = 1;
			break;
		default:
			printf("你输入有误，请重新输入：\n");
			break;
		}
	}
	printf("Bye Bye!\n");
	system("pause");
	return 0;
}

子函数：gama.c

#include "game.h"
void game()
{
	char mine[ROWS][COLS] = { 0 };
	char show[ROWS][COLS] = { 0 };
	memset(mine, '0', sizeof(mine));//初始化数组置为0
	memset(show, '*', sizeof(show));//初始化数组置为*	
	int no_y, no_x;
	set_mine(mine, ROWS, COLS, &no_x, &no_y);//布雷  ‘1’表示雷	
	int x = 0;
	int y = 0;
	int time = 100 - NUM;
	while (time > 0)
	{
		system("cls");//清屏		
		Show(show, ROWS, COLS);//打印 棋盘		
		printf("请输入坐标：\n");
		scanf("%d%d", &x, &y);
		if (x<1 || x>10 || y<1 || y>10)
		{
			printf("你输入有误，请重新输入：\n");
			continue;
		}
		if (show[x][y] != '*')
		{
			printf("你输入有误，请重新输入：\n");
			continue;
		}
		if (mine[x][y] == '1')
		{
			if (time == 80)//如果第一次有雷，用一个没雷的与这个交换			
			{
				mine[x][y] = '0';
				mine[no_y][no_y] = '1';
			}
			else
			{
				printf("game over!\n");
				Show(mine, ROWS, COLS);
				break;
			}
		}
		show[x][y] = get_mine_count(mine, x, y) + '0';
		time--;
	}

}
void set_mine(char mine[ROWS][COLS], int col, int row, int *no_x, int *no_y)//声明布雷函数
{
	int count = NUM;//设置计数器，统计布雷的个数
	while (count > 0)
	{
		int x = rand() % (col - 2) + 1;
		int y = rand() % (col - 2) + 1;
		if ((mine[x][y]) == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
	for (int i = 1; i <= 10; i++)
	{
		for (int j = 1; i <= 10; j++)
		{
			if (mine[i][j] == '0')
			{
				no_x = i;
				no_y = j;
				return;
			}
		}
	}
}
void Show(char mine[ROWS][COLS], int row, int col)//声明打印棋盘函数
{
	int i = 0;
	int j = 0;
	printf("    ");
	for (i = 1; i <= 10; i++)
	{
		printf("%2d |", i);
	}
	printf("\n");
	for (i = 1; i <= 11; i++)
	{
		printf("----");
	}
	printf("\n");
	for (i = 1; i <= 10; i++)
	{
		printf("%2d |", i);
		for (j = 1; j <= 10; j++)
		{
			printf("%2c |", mine[i][j]);
		}
		printf("\n");
		for (int i = 1; i <= 11; i++)
		{
			printf("----");
		}
		printf("\n");
	}
}
int get_mine_count(char mine[ROWS][COLS], int x, int y)//雷数统计
{
	return mine[x - 1][y - 1] + mine[x][y - 1] + \
		mine[x + 1][y - 1] + mine[x + 1][y]\
		+ mine[x + 1][y + 1] + mine[x][y + 1] + \
		+ mine[x - 1][y + 1] + mine[x - 1][y] - 8 * '0';
}