Compare Version Numbers(STRING-TYPE CONVERTION)

QUESTION

Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37
1ST TRY

class Solution {

public:

    int compareVersion(string version1, string version2) {

        int integer1 = 0;

        int integer2 = 0;

        int i1 = 0;

        int i2 = 0;

        

        while(i1 < version1.length())

        {

            integer1 = 10*integer1 + version1[i1++] - '0';

            if(version1[i1] == '.') 

            {

                i1++;

                break;

            }

        }

        while(i2 < version2.length())

        {

            integer2 = 10*integer2 + version2[i2++] - '0';

            if(version2[i2] == '.') 

            {

                i2++;

                break;

            }

        }

        if(integer1 > integer2) return 1;

        else if(integer1 < integer2) return -1;

        

        integer1 = 0;

        integer2 = 0;

        while(i1 < version1.length())

        {

            integer1 = 10*integer1 + version1[i1++] - '0';

        }

        while(i2 < version2.length())

        {

            integer2 = 10*integer2 + version2[i2++] - '0';

        }

        if(integer1 > integer2) return 1;

        else if(integer1 < integer2) return -1;

        else return 0;

    }

};

Result: Wrong

Input: "1.1", "1.01.0"
Output: -1
Expected: 0

2ND TRY

考虑有不只一个小数点的情况

class Solution {

public:

    int compareVersion(string version1, string version2) {

        int integer1 = 0;

        int integer2 = 0;

        int i1 = 0;

        int i2 = 0;

        

        while(i1 < version1.length() || i2 < version2.length())

        {

            while(i1 < version1.length())

            {

                integer1 = 10*integer1 + version1[i1++] - '0';

                if(version1[i1] == '.') 

                {

                    i1++;

                    break;

                }

            }

            while(i2 < version2.length())

            {

                integer2 = 10*integer2 + version2[i2++] - '0';

                if(version2[i2] == '.') 

                {

                    i2++;

                    break;

                }

            }

            if(integer1 > integer2) return 1;

            else if(integer1 < integer2) return -1;

            

            integer1 = 0;

            integer2 = 0;

        }

        return 0;

    }

};

Result: Accepted