python如何求解微分方程,如何使用Python内置函数odeint求解微分方程？

I want to solve this differential equations with the given initial conditions:

(3x-1)y''-(3x+2)y'+(6x-8)y=0, y(0)=2, y'(0)=3

the ans should be

y=2*exp(2*x)-x*exp(-x)

here is my code:

def g(y,x):

y0 = y[0]

y1 = y[1]

y2 = (6*x-8)*y0/(3*x-1)+(3*x+2)*y1/(3*x-1)

return [y1,y2]

init = [2.0, 3.0]

x=np.linspace(-2,2,100)

sol=spi.odeint(g,init,x)

plt.plot(x,sol[:,0])

plt.show()

but what I get is different from the answer.

what have I done wrong?

解决方案

There are several things wrong here. Firstly, your equation is apparently

(3x-1)y''-(3x+2)y'-(6x-8)y=0; y(0)=2, y'(0)=3

(note the sign of the term in y). For this equation, your analytical solution and definition of y2 are correct.

Secondly, as the @Warren Weckesser says, you must pass 2 parameters as y to g: y[0] (y), y[1] (y') and return their derivatives, y' and y''.

Thirdly, your initial conditions are given for x=0, but your x-grid to integrate on starts at -2. From the docs for odeint, this parameter, t in their call signature description:

odeint(func, y0, t, args=(),...):

t : array

A sequence of time points for which to solve for y. The initial

value point should be the first element of this sequence.

So you must integrate starting at 0 or provide initial conditions starting at -2.

Finally, your range of integration covers a singularity at x=1/3. odeint may have a bad time here (but apparently doesn't).

Here's one approach that seems to work:

import numpy as np

import scipy as sp

from scipy.integrate import odeint

import matplotlib.pyplot as plt

def g(y, x):

y0 = y[0]

y1 = y[1]

y2 = ((3*x+2)*y1 + (6*x-8)*y0)/(3*x-1)

return y1, y2

# Initial conditions on y, y' at x=0

init = 2.0, 3.0

# First integrate from 0 to 2

x = np.linspace(0,2,100)

sol=odeint(g, init, x)

# Then integrate from 0 to -2

plt.plot(x, sol[:,0], color='b')

x = np.linspace(0,-2,100)

sol=odeint(g, init, x)

plt.plot(x, sol[:,0], color='b')

# The analytical answer in red dots

exact_x = np.linspace(-2,2,10)

exact_y = 2*np.exp(2*exact_x)-exact_x*np.exp(-exact_x)

plt.plot(exact_x,exact_y, 'o', color='r', label='exact')

plt.legend()

plt.show()