目录
1、原理
(1)思维导图
(2)原理
2、案例及实现
(1)案例
(2)代码实现
(3)结果
3、误差分析及心得体会
import numpy as np
# 判断系数矩阵是否为非奇异矩阵
def IsItNonSingular(A):
row = len(A) # 系数矩阵行数
col = len(A[0]) # 系数矩阵列数
# 控制第i步,A矩阵为n阶方阵
for i in range(row - 1):
# 若主元元素为0,则进行行变换
if A[i][i] == 0:
# 从后往前找出主元为0的列中,首个不为零的行
# 对主元为0的行与此行进行行变换
Str = []
for h in range(row - 1, i, -1): # 添加该列所有元素
Str.append(A[h][i])
Num = col - Str.index(next(filter(lambda x: x != 0, Str)))
A[Num - 1], A[i] = A[i], A[Num - 1] # 做行变换
# 消元运算
for j in range(i + 1, row, 1):
coeff = A[j][i] / A[i][i]
for k in range(i, col, 1):
A[j][k] = A[j][k] - coeff * A[i][k] # 系数矩阵消元
# 判断该方程组系数矩阵是否为非奇异矩阵
for i in range(row):
if A[i][i] == 0:
print("Coefficient matrix is not a nonsingular matrix.")
return 'N'
print("Coefficient matrix is a nonsingular matrix.")
def GuassElimination(A, b):
row = len(A) # 系数矩阵行数
col = len(A[0]) # 系数矩阵列数
ε = 1E-5 # 定义一个小量
print("coefficient matrix:", A)
print("Constant column:", b)
# 控制第i步,高斯消元需要n-1步,A矩阵为n阶方阵
for i in range(row - 1):
if abs(A[i][i]) <= ε: # 若主元为一个小量,则采用列主消元
return None
# 消元运算
for j in range(i + 1, row, 1):
coeff = A[j][i] / A[i][i]
for k in range(i, col, 1):
A[j][k] = A[j][k] - coeff * A[i][k] # 系数矩阵消元
b[j] = b[j] - coeff * b[i] # 对应常数列消元
# 回代过程
x = [0] * col # 初始化元组,用于后面存放解
x[col - 1] = b[col - 1] / A[col - 1][col - 1] # 第n个解
for i in range(row - 2, -1, -1):
for j in range(col - 1, i, -1):
b[i] = b[i] - A[i][j] * x[j]
x[i] = b[i] / A[i][i]
print("The solution of the equations is:")
for i in range(col):
print("x{}:".format(i + 1), '%.8f' % x[i])
print("\n")
return x
def ColumnPrincipalElimination(A, b):
row = len(A) # 系数矩阵行数
col = len(A[0]) # 系数矩阵列数
print("coefficient matrix:", A)
print("Constant column:", b)
# 控制第i步,消元需要n-1步,A矩阵为n阶方阵
for i in range(row - 1):
# 每步运算前找出列中绝对值最大元素
# 作行变换,让绝对值最大的元素行作主元
Str = []
for j in range(i, row, 1):
Str.append(A[j][i])
Num = Str.index(max(Str)) + i
A[Num], A[i] = A[i], A[Num] # 行变换
b[Num], b[i] = b[i], b[Num]
# 消元运算
for j in range(i + 1, row, 1):
coeff = A[j][i] / A[i][i]
for k in range(i, col, 1):
A[j][k] = A[j][k] - coeff * A[i][k] # 系数矩阵消元
b[j] = b[j] - coeff * b[i] # 对应常数列消元
# 回代过程
x = [0] * col # 初始化元组,用于后面存放解
x[col - 1] = b[col - 1] / A[col - 1][col - 1] # 第n个解
for i in range(row - 2, -1, -1):
for j in range(col - 1, i, -1):
b[i] = b[i] - A[i][j] * x[j]
x[i] = b[i] / A[i][i]
print("The solution of the equations is:")
for i in range(col):
print("x{}:".format(i + 1), '%.8f' % x[i])
# print("\n")
return x
def main():
b1 = [0.4043, 0.1550, 0.4240, -0.2557]
b2 = [0.4043, 0.1550, 0.4240, -0.2557]
test1 = [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.1920, 0.3781, 0.0643],
[0.1784, 0.4002, 0.2785, 0.3927]]
test2 = [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.1920, 0.3781, 0.0643],
[0.1784, 0.4002, 0.2785, 0.3927]]
# python为动态语言,
# 在判断非奇异矩阵过程中会改动初值
# 故重新赋值
IsItNonSingular(test1)
print("test1 Gaussian elimination test:")
test1 = [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.1920, 0.3781, 0.0643],
[0.1784, 0.4002, 0.2785, 0.3927]]
GuassElimination(test1, b1)
IsItNonSingular(test2)
print("test2Gaussian column principal elimination test:")
test2 = [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.1920, 0.3781, 0.0643],
[0.1784, 0.4002, 0.2785, 0.3927]]
ColumnPrincipalElimination(test2, b2)
if __name__ == '__main__':
main()
Coefficient matrix is a nonsingular matrix.
test1 Gaussian elimination test:
coefficient matrix: [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.192, 0.3781, 0.0643], [0.1784, 0.4002, 0.2785, 0.3927]]
Constant column: [0.4043, 0.155, 0.424, -0.2557]
The solution of the equations is:
x1: -0.18034012
x2: -1.66163443
x3: 2.21499710
x4: -0.44669701
Coefficient matrix is a nonsingular matrix.
test2Gaussian column principal elimination test:
coefficient matrix: [[0.4096, 0.1234, 0.3678, 0.2943], [0.2246, 0.3872, 0.4015, 0.1129], [0.3645, 0.192, 0.3781, 0.0643], [0.1784, 0.4002, 0.2785, 0.3927]]
Constant column: [0.4043, 0.155, 0.424, -0.2557]
The solution of the equations is:
x1: -0.18034012
x2: -1.66163443
x3: 2.21499710
x4: -0.44669701
Process finished with exit code 0