【scipy】用python的库 scipy 求二重(多重)积分

scipy求一重积分：点击跳转.

sympy求积分：点击跳转.

问题1：求解如下二重积分

$$I={\int }_{y=0}^{1/2}{\int }_{x=0}^{1-2y}xydxdy.$$
程序1，如下：

from scipy.integrate import dblquad
area = dblquad(lambda x, y: x*y, 0, 0.5, 
               lambda x: 0, lambda x: 1-2*x)
print(area)

结果：(0.010416666666666668, 4.101620128472366e-16)

程序2，如下：

from scipy import integrate
def f(x, y):
    return x*y

def bounds_y():
    return [0, 0.5]

def bounds_x(y):
    return [0, 1-2*y]

print(integrate.nquad(f, [bounds_x, bounds_y]))

结果：0.010416666666666668, 4.101620128472366e-16)

问题2：求解如下三重积分

$$I={\int }_1^2{\int }_2^3{\int }_0^{1}xyzdxdydz.$$

程序1，如下

from scipy import integrate
f = lambda z, y, x: x*y*z
print(integrate.tplquad(f, 1, 2, lambda x: 2, lambda x: 3,
                  lambda x, y: 0, lambda x, y: 1))

结果：(1.8750000000000002, 3.324644794257407e-14)

程序2，如下

import scipy.integrate as integrate
def f(x,y,z):
    return x*y*z
def bounds_z():
    return [1, 2]
def bounds_y(*args):
    return [2, 3]
def bounds_x(*args):
    return [0, 1]
result = integrate.nquad(f, [bounds_x, bounds_y, bounds_z])
print(result)

结果：(1.8750000000000002, 3.324644794257407e-14)

问题3：求解如下四重积分

$$I={\int }_0^{1/2}{\int }_0^3{\int }_0^3{\int }_0^{3}xyztdxdydzdt.$$
程序，如下

import scipy.integrate as integrate
def f(x,y,z,t):
    return x*y*z*t
def bounds_z(*args):
    return [0, 1/2]
def bounds_y(*args):
    return [0, 3]
def bounds_x(*args):
    return [0, 3]
def bounds_t(*args):
    return [0,3]
result = integrate.nquad(f, [bounds_x, bounds_y, bounds_z, bounds_t])
print(result)

结果：(0.005208333333333334, 4.092713794698356e-16)