行列式计算c语言实现

//测试样例
/*
3
1 2 0
4 -3 8
0 -1 2


-14



4
1 -5 3 -3
2 0 1 -1
3 1 -1 2
4 1 3 -1


-55

10
1 0 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 20


11
1 0 0 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 0 1


20
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 20

*/


#include 
#include

void print1(int* det, int n);
int figure_serial1(int* det, int n);
int* det_son1(int* det, int a, int b, int n, int* c);

int main() {
	int n;
	printf("请输入n阶行列式的n的大小(n>0)：");
	scanf("%d", &n);

	if (n > 0) {

	}
	else {
		printf("输入错误!\n");
		return 0;
	}
	printf("请输入n阶行列式：\n");
	int* a = (int*)malloc(sizeof(int) * n * n);
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < n; j++) {
			scanf("%d", &a[i * n + j]);
		}
	}
	printf("行列式的计算结果是：%d\n", figure_serial1(a, n));

}
	void print1(int* det, int n) {
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < n; j++) {
				printf("%d ", det[i * n + j]);
			}
			printf("\n");
		}
		printf("\n");
	}

	//串行计算2（一位数组计算）
	int figure_serial1(int* det, int n)
	{
		int sum = 0;
		if (n == 2) {
			sum = det[0] * det[3] - det[1] * det[2];
			return sum;
		}
		for (int i = 0; i < n; i++)//用第一行展开计算
		{
			int flag = -1;
			if ((1 + i + 1) % 2 == 0) {
				flag *= -1;
			}
			int* c = (int*)malloc(sizeof(int) * n * n);
			int none = det[i] * figure_serial1(det_son1(det, 0, i, n, c), n - 1) * flag;
			//printf("none的值是%d\n", none);
			sum += none;
		}

		return sum;
	}

	//创建一维数组储存的行列式的余子式:
	int* det_son1(int* det, int a, int b, int n, int* c)
	{
		int q = 0;
		for (int i = 0; i < n; i++) {

			for (int j = 0; j < n; j++) {
				if (i == a || j == b)
				{
				}
				else
				{
					c[q] = det[i * n + j];
					q++;
				}

			}

		}
		// print1(c, n - 1);
		return c;
	}

用来算线代的行列式