iOS开发 - Swift中的Codable, Hashable, CaseIterable, Identifiable.....

去gayhub上浏览大佬的代码

struct Landmark: Hashable, Codable, Identifiable {
  ...
}

此时萌新的表情是这样的


0.jpeg

奥不对,是这样的

1.jpeg

今天我们就仔细分析下这几个。。。是干啥用的

首先 - Hashable

You can use any type that conforms to the Hashable protocol in a set or as a dictionary key.
只有遵循了Hashable 协议 才能被添加到 Set 中 或者用作 Dictionary 的 key 值

举个例子

// 假如我们有一个Person类
struct Person {
    var name: String
    var age: Int
}

// 假如我们有两位同学 小明 和 小红
let ming = Person(name: "ming", age: 10)
let hong = Person(name: "hong", age: 11)

// 现在我们有一个需求 1.把他加入到一个Set中  2. 用作Dictionary的key

// 我们这样写
var set: Set = []      //报错 Type 'Person' does not conform to protocol 'Hashable' 
set.insert(ming)
set.insert(hong)
print(set)

var dic: [Person: String] = [:]      //报错 Type 'Person' does not conform to protocol 'Hashable'
dic[ming] = ming.name              //报错 Referencing subscript 'subscript(_:)' on 'Dictionary' requires that 'Person' conform to 'Hashable'
dic[hong] = hong.name             //报错 Referencing subscript 'subscript(_:)' on 'Dictionary' requires that 'Person' conform to 'Hashable'
print(dic)

// 由于我们的Person并没有遵循Hashable协议,所以以上代码会报错
// 接下来 我们修改Person 
struct Person: Hashable {
    var name: String
    var age: Int
}

// 修改之后 ,以上报错会消失
// 打印结果为 set ---- [Test0.Person(name: "hong", age: 11), Test0.Person(name: "ming", age: 10)]
// dic --- [Test0.Person(name: "ming", age: 10): "ming", Test0.Person(name: "hong", age: 11): "hong"]
  • 拓展
// 假如我们的Person是一个Class而不是Struct,就必须要实现Hashable的协议方法
class Person: Hashable {
    // Hashable 继承自 Equatable,  此方法为Equatable的协议方法, 用来比较两个对象是否协议相等, 返回true的话 在Set或者Dictionary中都会被认为是同一个对象(在Set中会被去重, 在Dictionary中覆盖之前的值)
    static func == (lhs: Person, rhs: Person) -> Bool {
        return lhs.name == rhs.name && lhs.age == rhs.age
    }
    
    func hash(into hasher: inout Hasher) {
        hasher.combine(name)
        hasher.combine(age)
    }
    
    init(name: String, age: Int) {
        self.name = name
        self.age = age
    }
    
    var name: String
    var age: Int
}

举个栗子

// 还是之前的小明和小红
let ming = Person(name: "ming", age: 10)
let hong = Person(name: "hong", age: 11)

var set: Set = []
set.insert(ming)
set.insert(hong)
print(set)              // [Test0.Person, Test0.Person]

var dic: [Person: String] = [:]
dic[ming] = ming.name
dic[hong] = hong.name
print(dic)              // [Test0.Person: "hong", Test0.Person: "ming"]

// 因为ming1.name == ming.name && ming1.age == ming.age Person 的 static func == (lhs: Person, rhs: Person) -> Bool 方法成立 ming1 会覆盖之前的 ming
let ming1 = Person(name: "ming", age: 10)
set.insert(ming1)
dic[ming1] = ming1.name
print(set)              // [Test0.Person, Test0.Person]
print(dic)              // [Test0.Person: "hong", Test0.Person: "ming"]

// // 因为ming2.name == ming1.name && ming2.age == ming1.age Person 的 static func == (lhs: Person, rhs: Person) -> Bool 方法不成立 ming2 不会会覆盖之前的 1ming
let ming2 = Person(name: "ming", age: 20)
set.insert(ming2)
dic[ming2] = ming2.name
print(set)              // [Test0.Person, Test0.Person, Test0.Person]
print(dic)              // [Test0.Person: "hong", Test0.Person: "ming", Test0.Person: "ming"]

假如我们对Person进行修改 , 年龄相同就当做同一个人

class Person: Hashable {
    static func == (lhs: Person, rhs: Person) -> Bool {
//        return lhs.name == rhs.name && lhs.age == rhs.age
        return lhs.age == rhs.age
    }
    
    func hash(into hasher: inout Hasher) {
//        hasher.combine(name)
        hasher.combine(age)
    }
    
    init(name: String, age: Int) {
        self.name = name
        self.age = age
    }
    
    var name: String
    var age: Int
}

// 还是之前的小明和小红
let ming = Person(name: "ming", age: 10)
let hong = Person(name: "hong", age: 11)

var set: Set = []
set.insert(ming)
set.insert(hong)
print(set)              // [Test0.Person, Test0.Person]

var dic: [Person: String] = [:]
dic[ming] = ming.name
dic[hong] = hong.name
print(dic)              // [Test0.Person: "hong", Test0.Person: "ming"]

// 因为ming1.age == ming.age Person 的 static func == (lhs: Person, rhs: Person) -> Bool 方法成立 ming1 会覆盖之前的 ming
let ming1 = Person(name: "ming", age: 10)
set.insert(ming1)
dic[ming1] = ming1.name
print(set)              // [Test0.Person, Test0.Person]
print(dic)              // [Test0.Person: "hong", Test0.Person: "ming"]

// // 因为 ming2.age == ming1.age Person 的 static func == (lhs: Person, rhs: Person) -> Bool 方法成立 ming2 会覆盖之前的 1ming
let ming2 = Person(name: "aming", age: 10)
set.insert(ming2)
dic[ming2] = ming2.name
print(set)              // [Test0.Person, Test0.Person, Test0.Person]
print(dic)              // [Test0.Person: "hong", Test0.Person: "aming"]

其次 - Codable

在swift4之前,swift中数据解析的方式大都采用OC的KVC机制,swift4后可以采用Codable直接将json转成对象
先看定义

public typealias Codable = Decodable & Encodable

json转对象

struct Person: Codable {
    var name: String
    var age: Int
}

let jsonStr = "{\"name\" : \"ming\", \"age\" : 10}"
guard let jsonData = jsonStr.data(using: .utf8) else {
    exit(0)
}

let decoder = JSONDecoder()
guard let obj = try? decoder.decode(Person.self, from: jsonData) else {
    exit(0)
}

print(obj.name)    // ming
print(obj.age)     // 10

当json中的key值与我们定义的属性名对应时可以采用上述简单的方法, 如果不对应的话就需要借助CodingKeys来实现

// 修改Person
struct Person: Codable {
    var name: String
    var age: Int
    
    enum CodingKeys: String, CodingKey {
        case name = "a_name"
        case age = "age" //如果前后一致的话 可以省略=以及后边的部分 如 case age, 如果有需要忽略的key, 则不写到此处便可
    }
}

let decoder = JSONDecoder()
let jsonStr1 = "{\"a_name\" : \"ming\", \"age\" : 10}"
guard let jsonData1 = jsonStr1.data(using: .utf8) else {
    exit(0)
}

guard let obj1 = try? decoder.decode(Person.self, from: jsonData1) else {
    exit(0)
}

print(obj1.name)   // ming
print(obj1.age)    // 10

第三 - CaseIterable

swift4.2之后引进CaseIterable, 用于合成简单枚举类型的allCases静态属性
举个栗子

enum Week: CaseIterable {
    case Sun
    case Mon
    case Tue
    case Wen
    case Thu
    case Fri
    case Sat
}

print(Week.allCases)  // [Test0.Week.Sun, Test0.Week.Mon, Test0.Week.Tue, Test0.Week.Wen, Test0.Week.Thu, Test0.Week.Fri, Test0.Week.Sat]

我们也可以重写allCases方法 例如

enum Week: CaseIterable {
    case Sun
    case Mon
    case Tue
    case Wen
    case Thu
    case Fri
    case Sat
    
    static var allCases: [Week] {
        return [.Mon, .Tue, .Wen, .Thu, .Fri, Sat, Sun]
    }
}

print(Week.allCases) //[Test0.Week.Mon, Test0.Week.Tue, Test0.Week.Wen, Test0.Week.Thu, Test0.Week.Fri, Test0.Week.Sat, Test0.Week.Sun]
ming

至于 - Identifiable

1.jpeg

完全没搞懂呀, 仅仅是遵循了这个协议之后就必须有一个名为id的属性吗?然后呢。。。

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