Java并发工具类--Semaphore详解

Semaphore是啥?

贴个官方解释:

Semaphore用于限制可以访问某些资源(物理或逻辑的)的线程数目,其维护了一个许可证集合,有多少资源限制就维护多少许可证集合,假如这里有N个资源,那就对应于N个许可证,同一时刻也只能有N个线程访问。一个线程获取许可证就调用acquire方法,用完了释放资源就调用release方法。

举例

举个生活中的例子:

某餐厅只有3张餐桌,而当前需要接待的客人有6桌,那么就需要领号排队,结束一桌进去一桌,此处餐桌就相当于Semaphore的许可证。

通过代码实现上述过程:

public class SemaphoreTest {

    public static void main(String[] args) {
        ExecutorService service = Executors.newCachedThreadPool();
        Semaphore semaphore = new Semaphore(3);
        for(int i=0; i<6; i++){
            Runnable runnable = new Runnable() {
                @Override
                public void run() {
                    try{
                        // 获取令牌
                        System.out.println(System.currentTimeMillis() + ": " + Thread.currentThread().getName() + "尝试获取令牌");
                        semaphore.acquire();
                        System.out.println(System.currentTimeMillis() + ": " + Thread.currentThread().getName() + "获取到令牌,开始就餐");
                        Thread.sleep((long) (Math.random() * 10000));
                        System.out.println(System.currentTimeMillis() + ": " + Thread.currentThread().getName() + "就餐完毕,随后释放令牌");
                        semaphore.release();
                    }catch (InterruptedException ie){
                        ie.printStackTrace();
                    }

                }
            };
            service.execute(runnable);
        }
        service.shutdown();
    }
}

点击运行:

1595402085297: pool-1-thread-1尝试获取令牌
1595402085297: pool-1-thread-2尝试获取令牌
1595402085297: pool-1-thread-1获取到令牌,开始就餐
1595402085297: pool-1-thread-2获取到令牌,开始就餐
1595402085298: pool-1-thread-3尝试获取令牌
1595402085298: pool-1-thread-3获取到令牌,开始就餐
1595402085298: pool-1-thread-4尝试获取令牌
1595402085298: pool-1-thread-5尝试获取令牌
1595402085299: pool-1-thread-6尝试获取令牌
1595402088192: pool-1-thread-3就餐完毕,随后释放令牌
1595402088192: pool-1-thread-4获取到令牌,开始就餐
1595402091469: pool-1-thread-4就餐完毕,随后释放令牌
1595402091469: pool-1-thread-5获取到令牌,开始就餐
1595402091504: pool-1-thread-5就餐完毕,随后释放令牌
1595402091504: pool-1-thread-6获取到令牌,开始就餐
1595402092173: pool-1-thread-1就餐完毕,随后释放令牌
1595402094097: pool-1-thread-2就餐完毕,随后释放令牌
1595402094502: pool-1-thread-6就餐完毕,随后释放令牌

源码剖析

Semaphore是基于AQS共享锁来实现的,先看一下其构造函数:

public Semaphore(int permits) {
    sync = new NonfairSync(permits);
}

public Semaphore(int permits, boolean fair) {
    sync = fair ? new FairSync(permits) : new NonfairSync(permits);
}

可以看到,真正起作用的是NonfairSync和FairSync内部类,分别对应非公平锁和公平锁。

NonfairSync和FairSync均是Sync的继承类。

abstract static class Sync extends AbstractQueuedSynchronizer {
    private static final long serialVersionUID = 1192457210091910933L;
    
    // 构造函数传入令牌数
    Sync(int permits) {
        setState(permits);
    }
    // 获取令牌数
    final int getPermits() {
        return getState();
    }
    // 定义非公平版的TryAcquireShared方法
    final int nonfairTryAcquireShared(int acquires) {
        for (;;) {
            // 获取当前资源值
            int available = getState();
            // CAS尝试释放资源acquires
            int remaining = available - acquires;
            if (remaining < 0 ||
                compareAndSetState(available, remaining))
                return remaining;
        }
    }
    // CAS释放共享锁
    protected final boolean tryReleaseShared(int releases) {
        for (;;) {
            int current = getState();
            int next = current + releases;
            if (next < current) // overflow
                throw new Error("Maximum permit count exceeded");
            if (compareAndSetState(current, next))
                return true;
        }
    }
    // 减少令牌数
    final void reducePermits(int reductions) {
        for (;;) {
            int current = getState();
            int next = current - reductions;
            if (next > current) // underflow
                throw new Error("Permit count underflow");
            if (compareAndSetState(current, next))
                return;
        }
    }
    // 将令牌数归零
    final int drainPermits() {
        for (;;) {
            int current = getState();
            if (current == 0 || compareAndSetState(current, 0))
                return current;
        }
    }
}

先看非公平版的Sync:

static final class NonfairSync extends Sync {
    private static final long serialVersionUID = -2694183684443567898L;

    NonfairSync(int permits) {
        super(permits);
    }
    // 覆写AQS的tryAcquireShared方法,本质上调用的是Sync的nonfairTryAcquireShared
    protected int tryAcquireShared(int acquires) {
        return nonfairTryAcquireShared(acquires);
    }
}

接着看公平版的Sync:

static final class FairSync extends Sync {
    private static final long serialVersionUID = 2014338818796000944L;

    FairSync(int permits) {
        super(permits);
    }

    protected int tryAcquireShared(int acquires) {
        for (;;) {
            if (hasQueuedPredecessors())
                return -1;
            int available = getState();
            int remaining = available - acquires;
            if (remaining < 0 ||
                compareAndSetState(available, remaining))
                return remaining;
        }
    }
}

可以发现,FairSync的tryAcquireShared方法与Sync的nonfairTryAcquireShared方法相比,只是多了以下代码:

if (hasQueuedPredecessors())
    return -1;

当线程尝试获取共享锁时,首先判断AQS同步队列中是否有等待的线程,若有等待的线程,则直接返回-1。

接着看一下Semaphore如何获取令牌:

public void acquire() throws InterruptedException {
    sync.acquireSharedInterruptibly(1);
}

最终调用的Sync的acquireSharedInterruptibly的方法,acquireSharedInterruptibly是AQS中的方法:

public final void acquireSharedInterruptibly(int arg)
        throws InterruptedException {
    if (Thread.interrupted())
        throw new InterruptedException();
    if (tryAcquireShared(arg) < 0)
        doAcquireSharedInterruptibly(arg);
}

非公平锁模式下,tryAcquireShared方法会直接CAS尝试更新state获取共享锁,不管AQS同步队列中是否有阻塞线程,仅有当前资源为0时,tryAcquireShared(1)才会返回-1,进入到doAcquireSharedInterruptibly方法中。

而公平锁模式下,tryAcquireShared方法在CAS尝试更新state获取共享锁前,先检查AQS同步队列中是否有阻塞线程,若有,则直接返回-1,继续执行doAcquireSharedInterruptibly方法将当前线程添加到AQS同步队列中。

释放令牌的话:

public void release() {
    sync.releaseShared(1);
}

最终调用AQS的releaseShared方法。

所以,好好研究AQS,只要AQS理解透彻了,Java的这些并发工具类也就通透了。

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