LeetCode1043. 分隔数组以得到最大和

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解题思路:

 

class Solution {
public:

    int getMaxValue(int* arr, int start, int end) //找出一段区间内的最大数
    {
        int res = 0;
        for (int i = start; i <= end; i++) 
        {
            res = max(res, arr[i]);
        }

        return res;
    }


    int maxSumAfterPartitioning(vector& arr, int k) 
    {
        int length = arr.size();
        vector dp(length+1 , 0); //开辟空间+初始化

        for (int i = 1; i <= k; i++)  // i<=k还未到最大分隔数
        {
            dp[i] = getMaxValue(&arr[0] , 0 , i-1 ) * i;
        }
        
        for (int i = k+1; i <= length; i++) 
        {
            for (int j = 1; j <= k; j++) 
            {
                dp[i] = max(dp[i - j] +  getMaxValue(&arr[0] , i-j , i-1)  * j, dp[i]);
            }
        }

        return dp[length];
    }

};