2022-2-21 Leetcode 1221.分割平衡的字符串

class Solution {
public:
    int balancedStringSplit(string s) {
        int cnt = 0;
        int res = 0;
        for(auto &ch : s){
            if(ch == 'R'){
                cnt++;
            }else if(ch == 'L'){
                cnt--;
            }
            if(cnt == 0){
                res++;
            }
        }
        return res;
    }
};