Python-输出1~100之间的素数

for n in range(2,101):
    i,a=2,1
    while i

for m in range(2,101):
    a=1
    for n in range(2,m):
        if m%n==0:
            a=0
            break
    if a==1:
        print(m,end=' ')

for m in range(2,101):
    n=2
    while n