tup = (21, 19, 11, 46, 18)
print(tup)
lt = list(tup)
print(lt)
输出
(21, 19, 11, 46, 18)
[21, 19, 11, 46, 18]
# List of tuple initialization
listoftuples = [("Apple", 1), ("Microsoft", 2), ("Amazon", 3)]
# Using list comprehension
out = [item for t in listoftuples for item in t]
# Printing output
print(out)
输出
['Apple', 1, 'Microsoft', 2, 'Amazon', 3]
还可以使用 itertools.chain() 方法将元组列表转换为列表。
# Importing itertools
import itertools
# List of tuple initialization
tuple = [(11, 21), (31, 41), (51, 61)]
# tuple = [(11, ), (31, ), (51, )] 这种方式在链接数据库查询ID时得到的元组,可以转为列表,很方便
# Using itertools
out = list(itertools.chain(*tuple))
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# Printing output
print(out)
输出
[11, 21, 31, 41, 51, 61]
结论:当给定一个可迭代对象(如列表、元组、集合、范围等)时,list() 和 tuple() 返回一个新的列表和元组