C字符串练习题（6.3.1）

编写一个程序，从键盘上读入一个小于1000的正整数，然后创建并输出一个字符串，说明该整数的值。例如，输入941，程序产生的字符串是“Nine hundred and forty one”。

#include
#include
#include

 
void split_number(int n, int* digits, int* count);

void split_number(int n, int* digits, int* count) {

	int i = 0;

	while (n > 0) {
		digits[i++] = n % 10;
		n /= 10;
	}

	*count = i;

}

int main() {
  

	char unit_to_word[][6] = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };
    char ten_to_word[][8] = { "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" };
	int digits[4];
	int count;

	char strNum[100];

	int num = 0;
	printf("Please enter an integer less than 1000 and greater than 0\n ");
	int result = scanf_s("%d",&num);

	split_number(num, digits, &count);

	if (count == 1) {

		char* str  = unit_to_word[digits[0]-1];
		strcpy_s(strNum, str);
	}
	else if(count == 2)
	{
		char* str = ten_to_word[digits[1]-1];
		strcpy_s(strNum, str);
		strcat_s(strNum, " ");
		if (digits[0] != 0) {
			strcat_s(strNum, sizeof(strNum), unit_to_word[digits[0] - 1]);
		}
	
	}
	else
	{
		char* str = unit_to_word[digits[2]-1];
		strcpy_s(strNum, str);
		strcat_s(strNum, " handred ");
		if (digits[1] != 0) {
			strcat_s(strNum, " and ");
			strcat_s(strNum,sizeof(strNum), ten_to_word[digits[1] - 1]);
		}
		strcat_s(strNum, " ");
		if (digits[0] != 0) {
			strcat_s(strNum, sizeof(strNum), unit_to_word[digits[0] - 1]);
		}

	}
	
	printf("The number you entered is converted to English is:\n %s\n\n", strNum);

    return 0;
   
}