Leetcode-57. Insert Interval

题目

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:
Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

思路

将给定的Interval插入到数组中，然后进行合并，合并思路参照
http://blog.csdn.net/wanna_wsl/article/details/65939241

代码

bool cmp(Interval i1, Interval i2) {
    if(i1.start < i2.start)
        return true;
    else if(i1.start > i2.start)
        return false;
    else
        return i1.end < i2.end;
}

class Solution {
public:
    vector insert(vector& intervals, Interval newInterval) {
        vector res;
        intervals.push_back(newInterval);
        sort(intervals.begin(), intervals.end(), cmp);
        res.push_back(intervals[0]);
        for(int i=1; iif(intervals[i].start > res[res.size()-1].end) {
                res.push_back(intervals[i]);
            } else {
                int pend = max(intervals[i].end, res[res.size()-1].end);
                res[res.size()-1] = Interval(res[res.size()-1].start, pend);
            }
        }
        return res;
    }
};