代码随想录算法训练营20期|第四十四天|动态规划part06|● 完全背包● 518. 零钱兑换 II ● 377. 组合总和 Ⅳ

  •  完全背包
  •  518. 零钱兑换 II 
class Solution {
    public int change(int amount, int[] coins) {
        int[] dp = new int[amount + 1];
        dp[0] = 1;
        for (int i = 0; i < coins.length; i++) {
            for (int j = coins[i]; j <= amount; j++) {
                dp[j] += dp[j - coins[i]];
            }
        }
        return dp[amount];
    }
}
  •  377. 组合总和 Ⅳ  
class Solution {
    public int combinationSum4(int[] nums, int target) {
        int[] dp = new int[target + 1];
        dp[0] = 1;
        for (int i = 0; i <= target; i++) {
            for (int j = 0; j < nums.length; j++) {
                if (i >= nums[j]) {
                    dp[i] += dp[i - nums[j]];
                }
            }
        }
        return dp[target];
    }
}

你可能感兴趣的:(代码随想录二刷,动态规划,算法)