利用java8新特性,可以用简洁高效的代码来实现一些数据处理。
定义1个Apple对象:
public class Apple {
private Integer id;
private String name;
private BigDecimal money;
private Integer num;
public Apple(Integer id, String name, BigDecimal money, Integer num) {
this.id = id;
this.name = name;
this.money = money;
this.num = num;
}
}
添加一些测试数据:
List appleList = new ArrayList<>();//存放apple对象集合
Apple apple1 = new Apple(1,"苹果1",new BigDecimal("3.25"),10);
Apple apple12 = new Apple(1,"苹果2",new BigDecimal("1.35"),20);
Apple apple2 = new Apple(2,"香蕉",new BigDecimal("2.89"),30);
Apple apple3 = new Apple(3,"荔枝",new BigDecimal("9.99"),40);
appleList.add(apple1);
appleList.add(apple12);
appleList.add(apple2);
appleList.add(apple3);
1、分组
List里面的对象元素,以某个属性来分组,例如,以id分组,将id相同的放在一起:
//List 以ID分组 Map>
Map> groupBy = appleList.stream().collect(Collectors.groupingBy(Apple::getId));
System.err.println("groupBy:"+groupBy);
{1=[Apple{id=1, name='苹果1', money=3.25, num=10}, Apple{id=1, name='苹果2', money=1.35, num=20}], 2=[Apple{id=2, name='香蕉', money=2.89, num=30}], 3=[Apple{id=3, name='荔枝', money=9.99, num=40}]}
2、List转Map
id为key,apple对象为value,可以这么做:
/**
* List -> Map
* 需要注意的是:
* toMap 如果集合对象有重复的key,会报错Duplicate key ....
* apple1,apple12的id都为1。
* 可以用 (k1,k2)->k1 来设置,如果有重复的key,则保留key1,舍弃key2
*/
Map appleMap = appleList.stream().collect(Collectors.toMap(Apple::getId, a -> a,(k1,k2)->k1));
打印appleMap
{1=Apple{id=1, name='苹果1', money=3.25, num=10}, 2=Apple{id=2, name='香蕉', money=2.89, num=30}, 3=Apple{id=3, name='荔枝', money=9.99, num=40}}
3、过滤Filter
从集合中过滤出来符合条件的元素:
//过滤出符合条件的数据
List filterList = appleList.stream().filter(a -> a.getName().equals("香蕉")).collect(Collectors.toList());
System.err.println("filterList:"+filterList);
[Apple{id=2, name='香蕉', money=2.89, num=30}]
4、求和
将集合中的数据按照某个属性求和:
//计算 总金额
BigDecimal totalMoney = appleList.stream().map(Apple::getMoney).reduce(BigDecimal.ZERO, BigDecimal::add);
System.err.println("totalMoney:"+totalMoney); //totalMoney:17.48
5、查找流中最大 最小值
Collectors.maxBy 和 Collectors.minBy 来计算流中的最大或最小值。
Optional maxDish = Dish.menu.stream().
collect(Collectors.maxBy(Comparator.comparing(Dish::getCalories)));
maxDish.ifPresent(System.out::println);
ptional minDish = Dish.menu.stream().
collect(Collectors.minBy(Comparator.comparing(Dish::getCalories)));
minDish.ifPresent(System.out::println);
6、去重
import static java.util.Comparator.comparingLong;
import static java.util.stream.Collectors.collectingAndThen;
import static java.util.stream.Collectors.toCollection;
// 根据id去重
List unique = appleList.stream().collect(
collectingAndThen(
toCollection(() -> new TreeSet<>(comparingLong(Apple::getId))), ArrayList::new)
);
下表展示 Collectors 类的静态工厂方法。
引用 https://mp.weixin.qq.com/s/20K3pluRBhcAZTV8vN-sAA