Leetcode——数组的改变、移动练习

453. 最小操作次数使数组元素相等

本人答案超时

class Solution {
public:
    int minMoves(vector<int>& nums) {
        int len = nums.size();
        int count = 0;
        if (len == 1) {
            count = 0;
        }
        else {
            while (nums[0] != nums[1] || nums[len - 2] != nums[len - 1]) {
                for (int i = 0; i < len - 1; i++) {
                    nums[i]++;
                }
                sort(nums.begin(), nums.end());
                count++;
            }
        }
        return count;
    }
};

本题逆向思维，思路好难想，学习一下

665. 非递减数列

class Solution {
public:
    bool checkPossibility(vector<int>& nums) {
        int count = 0;
        for (int i = 0; i < nums.size() - 1; i++) {
            if (nums[i] > nums[i + 1]) {
                count++;
                if (i > 0 && nums[i + 1] < nums[i - 1]) {
                    nums[i + 1] = nums[i];
                }
            }
        }
        if (count <= 1) {
            return true;
        }
        else {
            return false;
        }
    }
};

283. 移动零

class Solution {
public:
    void moveZeroes(vector<int>& nums) {
        int len = nums.size(), left = 0, right = 0;
        while (right < len) {
            if (nums[right]) {
                swap(nums[left], nums[right]);
                left++;
            }
            right++;
        }
    }
};