【leetcode】2578.最小和分割

思路

总的来说，就是转成字符串再拆分为多个数字字符$[0,1,2,3,....]$。

• 从小到大，排一下序为 nums
• 2个数字，一人依次到 nums 里面去拿一个数
• 最后2个数字相加就是结果了

代码

class Solution {
public:
    int splitNum(int num) {
        
        std::string num_string = std::to_string(num);
     
        std::vector<int> nums;
        for (int i = 0; i < num_string.length(); ++i)
        {
            nums.push_back(int(num_string[i]-'0'));
        }

        // for (auto item : nums) cout << item << " ";
        sort(nums.begin(), nums.end(), less<int>());

        // for (auto item : nums) cout << item << " ";

        std::string firstNumStr;
        std::string secondNumStr;

        for (int i = 0; i < nums.size(); i+=2)
        {
            firstNumStr += (std::to_string(nums[i]));

            if (i + 1 >= nums.size()) break;
            secondNumStr += (std::to_string(nums[i + 1]));
        }

        int firstNum = std::stoi(firstNumStr);
        int secondNum = std::stoi(secondNumStr);

        return (firstNum + secondNum);
    }
};