项目代码
https://github.com/yinhai1114/Java_Learning_Code/tree/main/IDEA_Chapter13/src/com/yinhai/wrapper_/homework_
注意String是final的不能改变需要toCharArray改成char数组
返回String需要将char改成valueOf改为String
public class HomeWork01 {
public static void main(String[] args) {
String str = "0123456789";
//改变的是char,和str无关
try {
System.out.println(reverse(str,1,5));//0543216789
System.out.println(reverse(str,4,5));//0123546789
System.out.println(reverse(str,2,5));//0154326789
System.out.println(reverse(str,7,5));//0154326789
} catch (Exception e) {
System.out.println(e.getMessage());
return;
}
//想改变str直接str = rever(str,start,end);即可
}
public static String reverse(String str,int start,int end){
//需要对输入的参数做一个验证
if(!(str.length() > end && end > start && start > 0 && str!=null)){
throw new RuntimeException("参数不正确");
}
char[] chars = str.toCharArray();//返回的是new的
char temp;
for (int i = 0; i < (end - start) / 2 + 1; i++) {
if(start + i == end + i){
break;
}
temp = chars[start + i];
chars[start + i]= chars[end - i];
chars[end - i] = temp;
}
String str1 = String.valueOf(chars);
return str1;
}
}
和老师的代码原理大差不差
public class Homework01 {
public static void main(String[] args) {
//测试
String str = "abcdef";
System.out.println("===交换前===");
System.out.println(str);
try {
str = reverse(str, 1, 4);
} catch (Exception e) {
System.out.println(e.getMessage());
return;
}
System.out.println("===交换后===");
System.out.println(str);
}
/**
* (1) 将字符串中指定部分进行反转。比如将"abcdef"反转为"aedcbf"
* (2) 编写方法 public static String reverse(String str, int start , int end) 搞定
* 思路分析
* (1) 先把方法定义确定
* (2) 把 String 转成 char[] ,因为char[] 的元素是可以交换的
* (3) 画出分析示意图
* (4) 代码实现
*/
public static String reverse(String str, int start, int end) {
//对输入的参数做一个验证
//老韩重要的编程技巧分享!!!
//(1) 写出正确的情况
//(2) 然后取反即可
//(3) 这样写,你的思路就不乱
if(!(str != null && start >= 0 && end > start && end < str.length())) {
throw new RuntimeException("参数不正确");
}
char[] chars = str.toCharArray();
char temp = ' '; //交换辅助变量
for (int i = start, j = end; i < j; i++, j--) {
temp = chars[i];
chars[i] = chars[j];
chars[j] = temp;
}
//使用chars 重新构建一个String 返回即可
return new String(chars);
}
}
public class HomeWork02 {
public static void main(String[] args) {
Person person = new Person();
while (!person.enterInfo()) {}
}
}
class Person {
Scanner scanner = new Scanner(System.in);
private String name;
private String password;
private String mail;
public Person() {
}
public boolean enterInfo() {
try {
System.out.println("请输入名字长度为2 3 4");
judeName(scanner.next());
System.out.println("请输入六位密码");
judePassword(scanner.next());
System.out.println("请输入邮箱,带有@以及.且@在.之前");
judeMail(scanner.next());
} catch (Exception e) {
System.out.println(e.getMessage());
System.out.println("请重新尝试");
return false;
}
System.out.println("注册成功");
return true;
}
public void judeName(String name) {
if (2 <= name.length() && name.length() <= 4) {
this.name = name;
} else {
throw new RuntimeException("名字长度错误");
}
}
public void judePassword(String password) {
char[] chars = password.toCharArray();
if (chars.length != 6) {
throw new RuntimeException("密码长度错误");
}
for (int i = 0; i < chars.length; i++) {
if (!(chars[i] < 58 && chars[i] > 47)){
throw new RuntimeException("密码包含非数字元素");
}
}
this.password = String.valueOf(chars);
}
public void judeMail(String mail) {
int index1 = mail.lastIndexOf('@');
int index2 = mail.lastIndexOf('.');
if (index1 > index2) {
throw new RuntimeException("格式错误 @必须在.之前");
}
if(index1 == -1){
throw new RuntimeException("格式错误 必须含有@");
}
if(index2 == -1){
throw new RuntimeException("格式错误 必须含有.");
}
this.mail = mail;
}
}
老师的代码
public class Homework02 {
public static void main(String[] args) {
String name = "abc";
String pwd = "123456";
String email = "ti@[email protected]";
try {
userRegister(name,pwd,email);
System.out.println("恭喜你,注册成功~");
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
/**
* 输入用户名、密码、邮箱,如果信息录入正确,则提示注册成功,否则生成异常对象
* 要求:
* (1) 用户名长度为2或3或4
* (2) 密码的长度为6,要求全是数字 isDigital
* (3) 邮箱中包含@和. 并且@在.的前面
*
* 思路分析
* (1) 先编写方法 userRegister(String name, String pwd, String email) {}
* (2) 针对 输入的内容进行校核,如果发现有问题,就抛出异常,给出提示
* (3) 单独的写一个方法,判断 密码是否全部是数字字符 boolean
*/
public static void userRegister(String name, String pwd, String email) {
//再加入一些校验
if(!(name != null && pwd != null && email != null)) {
throw new RuntimeException("参数不能为null");
}
//过关
//第一关
int userLength = name.length();
if (!(userLength >= 2 && userLength <= 4)) {
throw new RuntimeException("用户名长度为2或3或4");
}
//第二关
if (!(pwd.length() == 6 && isDigital(pwd))) {
throw new RuntimeException("密码的长度为6,要求全是数字");
}
//第三关
int i = email.indexOf('@');
int j = email.indexOf('.');
if (!(i > 0 && j > i)) {
throw new RuntimeException("邮箱中包含@和. 并且@在.的前面");
}
}
//单独的写一个方法,判断 密码是否全部是数字字符 boolean
public static boolean isDigital(String str) {
char[] chars = str.toCharArray();
for (int i = 0; i < chars.length; i++) {
if (chars[i] < '0' || chars[i] > '9') {
return false;
}
}
return true;
}
}
public class HomeWork03 {
public static void main(String[] args) {
String name = "Yin xiao Hai";
printName(name);
}
public static void printName(String name){
if(name == null){
System.out.println("不能为空");
return;
}
//对接受的字符串分割
String[] str = name.split(" ");
if (str.length != 3){
System.out.println("输入的字符串格式不对");
return;
}
System.out.println(String.format("%s,%s .%c" ,str[2],str[0],str[1].toUpperCase().charAt(0)));
}
}
public class HomeWork04 {
public static void main(String[] args) {
int countA = 0;
int counta = 0;
int countNum = 0;
//转成数组判断
String name = "Yinhai#3612";
//也可以用str.charAt(i)
char[] names = name.toCharArray();
for (int i = 0; i < names.length; i++) {
if (names[i] <= 'Z' && names[i] >= 'A'){
countA++;
}
if (names[i] <= 'z' && names[i] >= 'a'){
counta++;
}
if (names[i] <= '9' && names[i] >= '0'){
countNum++;
}
}
System.out.println("该字符串共有" + countA + "个大写字母"
+ counta + "个小写字母" + countNum + "个数字");
}
}
错了一个 没有重写,就是用Object的equals,判断的是地址相等,还错了一个s1==s4看错了,然后就是最后的那个,会使用Builder在常量池内创建新的hellohspedu然后用t1指向value指向该常量池,在前面的String类中有讲,多看看。然后t2直接指向已经有的
public class HomeWork05 {
public static void main(String[] args) {
String s1 = "hspedu";
Animal a = new Animal(s1);
Animal b = new Animal(s1);
System.out.println(a == b);
System.out.println(a.equals(b));
System.out.println(a.name == b.name);
String s4 = new String("hspedu");
String s5 = "hspedu";
System.out.println(s1 == s4);
System.out.println(s4 == s5);
String t1 = "hello" + s1;
String t2 = "hellohspedu";
System.out.println(t1.intern() == t2);
}
}
class Animal {
String name;
public Animal(String name) {
this.name = name;
}
}