在浏览器通过网页拼接【/robots.txt】来了解可爬取的网页路径范围
例如访问: https://www.csdn.net/robots.txt
User-agent: *
Disallow: /scripts
Disallow: /public
Disallow: /css/
Disallow: /images/
Disallow: /content/
Disallow: /ui/
Disallow: /js/
Disallow: /scripts/
Disallow: /article_preview.html*
Disallow: /tag/
Disallow: /?
Disallow: /link/
Disallow: /tags/
Disallow: /news/
Disallow: /xuexi/
通过Python Requests 库发送HTTP【Hypertext Transfer Protocol “超文本传输协议”】请求
通过Python Beautiful Soup 库来解析获取到的HTML内容
HTTP请求
HTTP响应
import requests
# 解析HTML
from bs4 import BeautifulSoup
# 将程序伪装成浏览器请求
head = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64)"
}
requests = requests.get("http://books.toscrape.com/",headers= head)
# 指定编码
# requests.encoding= 'gbk'
if requests.ok:
# file = open(r'C:\Users\root\Desktop\Bug.html', 'w')
# file.write(requests.text)
# file.close
content = requests.text
## html.parser 指定当前解析 HTML 元素
soup = BeautifulSoup(content, "html.parser")
## 获取价格
all_prices = soup.findAll("p", attrs={"class":"price_color"})
for price in all_prices:
print(price.string[2:])
## 获取名称
all_title = soup.findAll("h3")
for title in all_title:
## 获取h3下面的第一个a元素
print(title.find("a").string)
else:
print(requests.status_code)
import requests
# 解析HTML
from bs4 import BeautifulSoup
head = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64)"
}
# 获取 TOP 250个电影名
for i in range(0,250,25):
response = requests.get(f"https://movie.douban.com/top250?start={i}", headers= head)
if response.ok:
content = response.text
soup = BeautifulSoup(content, "html.parser")
all_titles = soup.findAll("span", attrs={"class": "title"})
for title in all_titles:
if "/" not in title.string:
print(title.string)
else:
print(response.status_code)
import requests
# 解析HTML
from bs4 import BeautifulSoup
head = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64)"
}
response = requests.get(f"https://www.maoyan.com/", headers= head)
if response.ok:
soup = BeautifulSoup(response.text, "html.parser")
for img in soup.findAll("img", attrs={"class": "movie-poster-img"}):
img_url = img.get('data-src')
alt = img.get('alt')
path = 'img/' + alt + '.jpg'
res = requests.get(img_url)
with open(path, 'wb') as f:
f.write(res.content)
else:
print(response.status_code)