Java实现仿射密码加密解密
Java实现仿射密码加密解密
仿射密码
加密：将明文转化为对应的数字，如 ‘a’-> 0, ‘b’->1,…,’1’->26,’2’->27,…然后将数字进行仿射运算，求取出来的数字再转化为字符。即 密文=(K1*明文+K2)mod36
解密：密文转化为对应数字，然后进行仿射的逆运算，得到对应数字，然后将其转化为字符明文。解密 K3是K1的乘法逆元
import java.util.Scanner;
public class Affine{
public static void main(String[] args) {
char[] form = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N',
'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', '0'
, '1', '2', '3', '4', '5', '6', '7', '8', '9'};
Scanner sc = new Scanner(System.in);
System.out.println("请输入待加密的明文：");
String MingWen = sc.nextLine();
MingWen=MingWen.toUpperCase();//将输入的明文全部大写
final int K1 = 103;
final int K2 = 103;
final int K3 = 7;
int [] cipherNum=new int[MingWen.length()];//用来存储数字化的密文
encryption(MingWen,form,K1,K2,cipherNum);
decryption(form,MingWen,K2,K3,cipherNum);
}
public static void encryption(String MingWen,char[] form,int K1,int K2,int[] cipherNum){
//第一步：将明文存入数组
char[] pla=new char[MingWen.length()];
for (int i = 0; i