Spring Boot 3 + Spring Security 6 最新版本修改 Json 登录后 RememberMe 功能问题失效的解决方案

当 Spring Boot 版本更新到 3 之后,最低要求的 JDK 版本变为 17,相应的 最新版本的 Spring Security 的配置也发生了变化,一下主要讲解一些新的 Spring Security 的配置方法

1. 配置由继承WebSeucrityConfigurerAdapter变成只需添加一个SecurityFilterChainbean即可。

  1. Remember Me Token Repository
@Bean
public PersistentTokenRepository tokenRepositoryByMemory() {
  return new InMemoryTokenRepositoryImpl();
}
  1. SecurityHandler 工具
public class SecurityHandler {
  public void onLoginSuccess(
    final HttpServletRequest request,
    final HttpServletResponse response,
    final Authentication authentication) {
    sendUtf8MessageToResponse(response, RespMessage.success(
      "User " + authentication.getName() + " login success."));
  }

  public void onLoginFailure(
    final HttpServletRequest request,
    final HttpServletResponse response,
    final AuthenticationException exception) {
    log.error("Login failure, {}.", exception.getMessage());
    sendUtf8MessageToResponse(response, RespMessage.failure(
      "Login failure: " + exception.getMessage()));
  }

  public void onAuthenticationFailure(
    final HttpServletRequest request,
    final HttpServletResponse response,
    final AuthenticationException exception) {
    log.error("Auth failure, {}.", exception.getMessage());
    sendUtf8MessageToResponse(response, RespMessage.failure(
      HttpStatus.UNAUTHORIZED, "Auth failure: " + exception.getMessage()));
  }

  public void onAccessDenied(
    final HttpServletRequest request,
    final HttpServletResponse response,
    final AccessDeniedException exception) {
    log.error("Access denied, {}.", exception.getMessage());
    sendUtf8MessageToResponse(response, RespMessage.failure(
      HttpStatus.FORBIDDEN, "Access denied: " + exception.getMessage()));
  }

  public void onLogoutSuccess(
    final HttpServletRequest request,
    final HttpServletResponse response,
    final Authentication authentication) {
    RespMessage<String> resp;
    if (Objects.nonNull(authentication)) {
      resp = RespMessage.success("Logout success: " + authentication.getName() + ".");
    } else {
      log.error("Logout failure: Unauthorized logout request.");
      resp = RespMessage.failure(HttpStatus.UNAUTHORIZED, "Unauthorized logout request.");
    }
    sendUtf8MessageToResponse(response, resp);
  }

  public CorsConfigurationSource configurationSource() {
    final CorsConfiguration corsConfiguration = new CorsConfiguration();
    corsConfiguration.addAllowedOriginPattern("*");
    corsConfiguration.setAllowCredentials(true);
    corsConfiguration.addAllowedHeader("*");
    corsConfiguration.addAllowedMethod("*");
    corsConfiguration.addExposedHeader("*");
    final UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
    source.registerCorsConfiguration("/**", corsConfiguration);
    return source;
  }

  private void sendUtf8MessageToResponse(
    final HttpServletResponse response,
    final RespMessage<?> respMessage) {
    response.setContentType(APPLICATION_JSON_VALUE);
    try {
      JSONUtil.toJsonStr(respMessage, response.getWriter());
    } catch (final IOException e) {
      log.error("Write To Response Failure: {}.", e.getMessage());
    }
  }
}

  1. UserDetailService
@Bean
public UserDetailsService userDetailsService() {
  final PasswordEncoder encoder = PasswordEncoderFactories.createDelegatingPasswordEncoder();
  final UserBuilder users = User.builder().passwordEncoder(encoder::encode);
  final InMemoryUserDetailsManager manager = new InMemoryUserDetailsManager();
  manager.createUser(users.username("user").password("password").roles("USER").build());
  manager.createUser(users.username("admin").password("password").roles("USER","ADMIN").build());
  return manager;
}
  1. Spring Srcurity 配置类
@Bean
public SecurityFilterChain filterChain(final HttpSecurity httpSecurity) throws Exception {
  // 解决 Json 数据返回中文乱码问题
  final CharacterEncodingFilter encodingFilter = new CharacterEncodingFilter();
  encodingFilter.setEncoding(StandardCharsets.UTF_8.name());
  encodingFilter.setForceEncoding(true);

  return httpSecurity
    .addFilterBefore(encodingFilter, CsrfFilter.class)
    .authorizeHttpRequests(auth -> auth.anyRequest().authenticated())
    .formLogin(formLogin -> formLogin
        .loginProcessingUrl("/auth/login")
        .successHandler(securityHandler::onLoginSuccess)
        .failureHandler(securityHandler::onLoginFailure)
        .permitAll()
    )
    .logout(logout -> logout
         .logoutUrl("/auth/logout")
         .logoutSuccessHandler(securityHandler::onLogoutSuccess)
     )
    .exceptionHandling(exception -> {
      exception.authenticationEntryPoint(securityHandler::onAuthenticationFailure);
      exception.accessDeniedHandler(securityHandler::onAccessDenied);
    })
    .cors(corsConfig -> corsConfig.configurationSource(securityHandler.configurationSource()))
    .rememberMe(rememberMeConfig -> {
      rememberMeConfig.rememberMeParameter("remember");
      rememberMeConfig.userDetailsService(userDetailsService);
      rememberMeConfig.tokenRepository(tokenRepository);
      // 设置短一点的时间以测试 remember-me 的功能
      rememberMeConfig.tokenValiditySeconds(30);
    })
    .csrf(AbstractHttpConfigurer::disable)
    .sessionManagement(AbstractHttpConfigurer::disable)
    .build();
}
  1. TestController ebdpoint
@GetMapping("system-resource")
public RespMessage<String> getSystemResource() {
  log.info("Invoke system-resource api, get resource success.");
  return RespMessage.success("Congratulation get the system resource.");
}

2. login 请求测试,可以看到 remember-me cookie 成功返回,并且在下一次求中会携带该 token 去服务器端,在 cookie 的有效期内直接自动登录

Spring Boot 3 + Spring Security 6 最新版本修改 Json 登录后 RememberMe 功能问题失效的解决方案_第1张图片
在这里插入图片描述

3. 将 login 请求更改成以 Json 字符串的格式提交的形式

  1. RequestUtil 工具类
public final class RequestUtil {
  private RequestUtil() {}

  public static LoginRequest getLoginRequest(final HttpServletRequest request) {
    final ObjectMapper objectMapper = new ObjectMapper();
    try {
      return objectMapper.readValue(request.getInputStream(), LoginRequest.class);
    } catch (final Exception e) {
      log.error("Read LoginRequest Value Error: {}.", e.getMessage());
      throw new AuthenticationServiceException(e.getMessage());
    }
  }
}
  1. 自定义 UsernamePasswordAuthenticationFilter
public class JsonUsernamePasswordAuthenticationFilter extends UsernamePasswordAuthenticationFilter {
  @Override
  public Authentication attemptAuthentication(
    final HttpServletRequest request,
    final HttpServletResponse response) throws AuthenticationException {

    if (!StrUtil.equalsIgnoreCase(HttpMethod.POST.name(), request.getMethod())
        || !StrUtil.equalsIgnoreCase(APPLICATION_JSON_VALUE, request.getContentType())) {
      throw new AuthenticationServiceException(
        "Authentication method or content type not supported: " + request.getMethod()
        + ", " + request.getContentType());
    }

    final LoginRequest loginRequest = RequestUtil.getLoginRequest(request);

    final UsernamePasswordAuthenticationToken authRequest =
      new UsernamePasswordAuthenticationToken(
      loginRequest.getUsername(), loginRequest.getPassword());

    setDetails(request, authRequest);

    return getAuthenticationManager().authenticate(authRequest);
  }
}
  1. 添加自定义 UsernamePasswordAuthenticationFilter 到 IOC 容器中
private final SecurityHandler securityHandler;

@Bean
public UsernamePasswordAuthenticationFilter usernamePasswordAuthenticationFilter() {
  final JsonUsernamePasswordAuthenticationFilter filter =
    new JsonUsernamePasswordAuthenticationFilter();
  filter.setFilterProcessesUrl("/auth/login");
  filter.setAuthenticationSuccessHandler(securityHandler::onLoginSuccess);
  filter.setAuthenticationFailureHandler(securityHandler::onLoginFailure);
  filter.setAuthenticationManager(authenticationManager());
  filter.setSecurityContextRepository(new HttpSessionSecurityContextRepository());
  return filter;
}
  1. 更改 Spring Security 配置类
// 将以下部分
.formLogin(formLogin -> formLogin
    .loginProcessingUrl("/auth/login")
    .successHandler(securityHandler::onLoginSuccess)
    .failureHandler(securityHandler::onLoginFailure)
    .permitAll()
)
// 替换成以下部分即可
.formLogin(AbstractHttpConfigurer::disable)
.addFilterBefore(usernamePasswordAuthenticationFilter, UsernamePasswordAuthenticationFilter.class)

4. 发现问题:我们配置了开启了 SpringSecurity 的 remember 功能,为啥不生效了呢?

  1. 我们只是将 formLogin 给关闭了<.formLogin(AbstractHttpConfigurer::disable)>,使用了自定义的 Json 格式来获取用户名和密码等信息,并且携带了 remember 的信息过来。

  2. 如果我们保持这个自定义登录的配置不变,仅仅只加上.formLogin(form -> {})这一句话,其实 remember-me 功能已经解决了,虽然这可以解决问题,但这不是我们想要的,我们不就是需要自定义登录,把 formLogin 给关了吗?

  3. 关闭了 formLogin 到底做了什么呢?就导致了 remember-me 不生效了呢,参数获取方式需要变了是一个原因,但还有其他的。

  4. 在源码 UsernamePasswordAuthenticationFilter 的 attemptAuthentication 方法断点查看变量发现如下:

    1. 使用 formLogin 配置的时候,rememberMeServices 是 PersistentTokenBaseRememberMeServices 实现的
      Spring Boot 3 + Spring Security 6 最新版本修改 Json 登录后 RememberMe 功能问题失效的解决方案_第2张图片

    2. 使用 Json 格式自定义登录的时候,rememberMeServices 是 NullRememberMeServices 实现的
      Spring Boot 3 + Spring Security 6 最新版本修改 Json 登录后 RememberMe 功能问题失效的解决方案_第3张图片

    3. 所以问题就出在这,当我们验证用户名密码之前,我们关闭了 formLogin 的话就没有正确配置好 rememberMeServices 的值

    4. 自定义 RememberMeServices

    @Component
    public class CustomJsonRememberMeService extends PersistentTokenBasedRememberMeServices {
    
      private static final String REMEMBER_ME_ATTR_NAME = "remember";
    
      private static final Integer REMEMBER_ME_TOKEN_VALIDITY = 3600;
    
      public CustomJsonRememberMeService(
        final UserDetailsService userDetailsService,
        final PersistentTokenRepository tokenRepository) {
        super(UUID.randomUUID().toString(), userDetailsService, tokenRepository);
        setParameter(REMEMBER_ME_ATTR_NAME);
        setTokenValiditySeconds(REMEMBER_ME_TOKEN_VALIDITY);
      }
    
      @Override
      protected boolean rememberMeRequested(final HttpServletRequest request, final String parameter) {
        final Object remember = request.getAttribute(REMEMBER_ME_ATTR_NAME);
        return Objects.nonNull(remember) && Boolean.parseBoolean(remember.toString());
      }
    }
    
    1. 修改 Security remember me 部分配置
    // 只需要将以下部分
    .rememberMe(rememberMeConfig -> {
      rememberMeConfig.rememberMeParameter("remember");
      rememberMeConfig.userDetailsService(userDetailsService);
      rememberMeConfig.tokenRepository(tokenRepository);
      rememberMeConfig.tokenValiditySeconds(30);
    })
    
    // 更改成以下部分即可,这里将 userDetailsService 和 tokenRepository 都移除了是因为 customJsonRememberMeService 已经定义好了这两个的实现了
    private final RememberMeServices rememberMeServices;
    .rememberMe(rememberMeConfig -> rememberMeConfig.rememberMeServices(rememberMeServices))
    
    1. 修改 JsonUsernamePasswordAuthenticationFilter 部分
    // 在获取 LoginRequest 对象之后,再从 LoginRequest 中获取 remember 的值并且存进 request 中以便 CustomJsonRememberMeService 中获取
    final LoginRequest loginRequest = RequestUtil.getLoginRequest(request);
    
    // 以下是添加的代码
    if (loginRequest.getRemember()) {
      request.setAttribute("remember", true);
    }
    
  5. 再使用 PostMan 调用接口已经生效了

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