第15周

1计算零件数

#include
 
int main()
{
    int total;
    for (int i = 11; i < 23; i++)
    {
        total = i * 9 + 5;
        if (total % 4 == 2 && total % 7 == 3)
        {
            printf("%d\n", total);
            return 0;
        }
    }
    return 0;
}

2走台阶

#include
 
int step(int n);

int main()
{
    int a;
    a = step(10);
    printf("Result=%d", a);
    return 0;
}

int step(int n)
{
    if (n == 1)
        return 1;
    if (n == 2)
        return 2;
    else
        return step(n - 1) + step(n - 2);
}

3将数据按照奇偶排序

#include
 

int main()
{
    int old[10];
    int new[10];
    int temp;
    int count = 0;
    printf("Input 10 numbers:\n");
    for (int i = 0; i < 10; i++)
    {
        scanf("%d", &old[i]);
    }
    for (int i = 0; i < 9; i++)
    {
        for (int j = 0; j < 10-i-1; j++)
        {
            if (old[j] > old[j + 1])
            {
                temp = old[j]; old[j] = old[j + 1]; old[j + 1] = temp;
            }
        }
    }
    for (int i = 0; i < 10; i++)
    {
        if (old[i] % 2 != 0)
        {
            new[count] = old[i];
            count++;
        }
    }
    for (int i = 0; i < 10; i++)
    {
        if (old[i] % 2 == 0)
        {
            new[count] = old[i];
            count++;
        }
    }
    printf("Output: ");
    for (int i = 0; i < 9; i++)
        printf("%d,", new[i]);
    printf("%d\n", new[9]);
    return 0;
}

4三色球分组

#include
 

int main()
{
    int red = 0;
    int white = 0;
    int black = 0;
    int count = 0;
    printf("The result:\n");
    for (red = 1; red < 4; red++)
        for (white = 1; white < 6; white++)
            for (black = 0; black < 7; black++)
                if (red + white + black == 8)
                {
                    printf("red:%4d white:%4d black:%4d\n", red, white, black);
                    count++;
                }
    printf("sum=%4d\n", count);
                    
    return 0;
}

5同构数

#include
 

int main()
{
    int i;
    for (i = 1; i < 100; i++)
    {
        if (i < 10)
        {
            if (i == (i * i) % 10)
                printf("m=%3d\t\tm*m=%6d\n", i, i * i);
        }
        else
        {
            if (i == (i*i)%100)
                printf("m=%3d\t\tm*m=%6d\n", i, i * i);
        }
    }
    return 0;
}