基于方向键实现矩阵选择

4*3

要实现上下左右OK五个按键来操作一个4x3矩阵，您可以按照类似的思路进行编程。以下是一个示例代码：

#include 

#define ROWS 4
#define COLS 3

int matrix[ROWS][COLS] = {
    {1, 2, 3},
    {4, 5, 6},
    {7, 8, 9},
    {10, 11, 12}
};

void printMatrix() {
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            printf("%-2d ", matrix[i][j]);
        }
        printf("\n");
    }
    printf("\n");
}

void moveUp() {
    int temp[COLS];
    for (int j = 0; j < COLS; j++) {
        temp[j] = matrix[0][j];
    }
    for (int i = 0; i < ROWS - 1; i++) {
        for (int j = 0; j < COLS; j++) {
            matrix[i][j] = matrix[i + 1][j];
        }
    }
    for (int j = 0; j < COLS; j++) {
        matrix[ROWS - 1][j] = temp[j];
    }
}

void moveDown() {
    int temp[COLS];
    for (int j = 0; j < COLS; j++) {
        temp[j] = matrix[ROWS - 1][j];
    }
    for (int i = ROWS - 1; i > 0; i--) {
        for (int j = 0; j < COLS; j++) {
            matrix[i][j] = matrix[i - 1][j];
        }
    }
    for (int j = 0; j < COLS; j++) {
        matrix[0][j] = temp[j];
    }
}

void moveLeft() {
    int temp[ROWS];
    for (int i = 0; i < ROWS; i++) {
        temp[i] = matrix[i][0];
    }
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS - 1; j++) {
            matrix[i][j] = matrix[i][j + 1];
        }
    }
    for (int i = 0; i < ROWS; i++) {
        matrix[i][COLS - 1] = temp[i];
    }
}

void moveRight() {
    int temp[ROWS];
    for (int i = 0; i < ROWS; i++) {
        temp[i] = matrix[i][COLS - 1];
    }
    for (int i = 0; i < ROWS; i++) {
        for (int j = COLS - 1; j > 0; j--) {
            matrix[i][j] = matrix[i][j - 1];
        }
    }
    for (int i = 0; i < ROWS; i++) {
        matrix[i][0] = temp[i];
    }
}

void pressOK() {
    int sum = 0;
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            sum += matrix[i][j];
        }
    }
    printf("Sum: %d\n", sum);
}

int main() {
    int choice;

    while (1) {
        printMatrix();
        printf("Press 1: Up, 2: Down, 3: Left, 4: Right, 5: OK\n");
        printf("Enter your choice: ");
        scanf("%d", &choice);

        switch (choice) {
            case 1:
                moveUp();
                break;
            case 2:
                moveDown();
                break;
            case 3:
                moveLeft();
                break;
            case 4:
                moveRight();
                break;
            case 5:
                pressOK();
                break;
            default:
                printf("Invalid choice!\n");
        }

        printf("\n");
    }

    return 0;
}

这个示例与之前的示例非常相似，只是调整了矩阵的行和列的顺序，以适应4x3的矩阵。移动操作的实现也有一些微调。

3*4

要实现上下左右OK五个按键来操作一个3x4矩阵，您可以使用一个二维数组来表示该矩阵，并利用按键输入来进行矩阵操作。以下是一个示例代码：

#include 

#define ROWS 3
#define COLS 4

int matrix[ROWS][COLS] = {
    {1, 2, 3, 4},
    {5, 6, 7, 8},
    {9, 10, 11, 12}
};

void printMatrix() {
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            printf("%-2d ", matrix[i][j]);
        }
        printf("\n");
    }
    printf("\n");
}

void moveUp() {
    int temp = matrix[0][0];
    for (int i = 0; i < ROWS - 1; i++) {
        for (int j = 0; j < COLS; j++) {
            matrix[i][j] = matrix[i + 1][j];
        }
    }
    for (int j = 0; j < COLS; j++) {
        matrix[ROWS - 1][j] = temp;
    }
}

void moveDown() {
    int temp = matrix[ROWS - 1][0];
    for (int i = ROWS - 1; i > 0; i--) {
        for (int j = 0; j < COLS; j++) {
            matrix[i][j] = matrix[i - 1][j];
        }
    }
    for (int j = 0; j < COLS; j++) {
        matrix[0][j] = temp;
    }
}

void moveLeft() {
    int temp = matrix[0][0];
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS - 1; j++) {
            matrix[i][j] = matrix[i][j + 1];
        }
    }
    for (int i = 0; i < ROWS; i++) {
        matrix[i][COLS - 1] = temp;
    }
}

void moveRight() {
    int temp = matrix[0][COLS - 1];
    for (int i = 0; i < ROWS; i++) {
        for (int j = COLS - 1; j > 0; j--) {
            matrix[i][j] = matrix[i][j - 1];
        }
    }
    for (int i = 0; i < ROWS; i++) {
        matrix[i][0] = temp;
    }
}

void pressOK() {
    int sum = 0;
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            sum += matrix[i][j];
        }
    }
    printf("Sum: %d\n", sum);
}

int main() {
    int choice;

    while (1) {
        printMatrix();
        printf("Press 1: Up, 2: Down, 3: Left, 4: Right, 5: OK\n");
        printf("Enter your choice: ");
        scanf("%d", &choice);

        switch (choice) {
            case 1:
                moveUp();
                break;
            case 2:
                moveDown();
                break;
            case 3:
                moveLeft();
                break;
            case 4:
                moveRight();
                break;
            case 5:
                pressOK();
                break;
            default:
                printf("Invalid choice!\n");
        }

        printf("\n");
    }

    return 0;
}

在这个示例中，我们定义了一个3x4矩阵matrix，以及相应的按键操作函数。printMatrix函数用于打印矩阵。moveUp、moveDown、moveLeft、moveRight函数分别实现了上、下、左、右按键的移动操作，将矩阵按指定方向进行移动。pressOK函数用于计算矩阵中所有元素的和。

在main函数中，我们通过一个循环来接受用户的按键输入，并根据选择调用相应的按键操作函数或打印矩阵的和。