HDOJ 3622 - Bomb Game 2-sat+二分....细心...

       题意:

                 有N个炸弹..每个炸弹有两个位置可以选择..把炸弹放到其中一个地方去...炸弹的爆炸范围是其为圆心的圆...两个炸弹不能有攻击范围上的重合..问要满足条件..炸弹爆炸范围的半径最长能是多少...

       题解:

                 每个炸弹看成一类..其在两个中比选一个..符合2-sat的构图条件....那么就二分枚举炸弹的爆炸范围..枚举相互是否干扰来做边构造2-sat模型...tarjan来判断是否合法..

                 题目不难..但是我2B了...在初始化vector时..for (i=0;i<(n<<1);i++)  T[i].clear() 写成了for (i=0;i<(1<<n);i++)  T[i].clear()...搞得我查了好久的错误..还写了几个版本的代码..这道题不好自己出数据..搞得很郁闷..最后怀疑是vector使用的问题..就索性写了个链表..结果就A了~~再反过头来看..发现了错误的根源...弱啊......


Program-----链表存图..整个程序int型计算..结果再开方除2输出

 

#include<iostream>

#include<stdio.h>

#include<string.h>

#include<cmath>

#include<queue>

#include<stack>

#include<set>

#include<map>

#include<algorithm>

#define ll long long

#define oo 1000000007

#define pi acos(-1.0)

#define MAXN 205

#define MAXM 100005

using namespace std;

struct node

{

       int x0,y0,x1,y1;

}b[MAXN];

struct LINE

{

       int x,y,next;

}line[MAXM];

int Lnum,_next[MAXN],dfn[MAXN],low[MAXN],tp[MAXN],tpnum,DfsIndex,arc[MAXN][MAXN];

bool instack[MAXN];

stack<int>  mystack;

int dis(int x0,int y0,int x1,int y1)

{

       return (x0-x1)*(x0-x1)+(y0-y1)*(y0-y1);

}

void addline(int x,int y)

{

       line[++Lnum].next=_next[x],_next[x]=Lnum;

       line[Lnum].x=x,line[Lnum].y=y;

}

void tarjan(int x)  

{  

       int y,k;

       dfn[x]=low[x]=++DfsIndex;  

       instack[x]=true;  

       mystack.push(x);  

       for (k=_next[x];k;k=line[k].next)

       {  

              y=line[k].y;  

              if (!dfn[y])  

              {  

                  tarjan(y);  

                  low[x]=min(low[x],low[y]);  

              }else   

                  if (instack[y]) low[x]=min(low[x],dfn[y]);  

       }  

       if (dfn[x]==low[x])  

       {  

              tpnum++;  

              do  

              {  

                    x=mystack.top();  

                    mystack.pop();  

                    instack[x]=false;  

                    tp[x]=tpnum;  

              }while (dfn[x]!=low[x]);  

       }  

       return;  

}  

bool _2sat(int n,int d)

{

       int i,j; 

       Lnum=0;

       memset(_next,0,sizeof(_next));

       for (i=0;i<n;i++)

          for (j=i+1;j<n;j++)

          {   

                  if (arc[i<<1][j<<1]<d)

                      addline(i<<1,j<<1|1),addline(j<<1,i<<1|1);

                  if (arc[i<<1][j<<1|1]<d)

                      addline(i<<1,j<<1),addline(j<<1|1,i<<1|1);

                  if (arc[i<<1|1][j<<1]<d)

                      addline(i<<1|1,j<<1|1),addline(j<<1,i<<1);

                  if (arc[i<<1|1][j<<1|1]<d)

                      addline(i<<1|1,j<<1),addline(j<<1|1,i<<1);

          }

       memset(dfn,0,sizeof(dfn));

       memset(instack,false,sizeof(instack));

       while (!mystack.empty()) mystack.pop();

       tpnum=DfsIndex=0;

       for (i=0;i<(n<<1);i++)

           if (!dfn[i]) tarjan(i);

       for (i=0;i<n;i++)

           if (tp[i<<1]==tp[i<<1|1]) return false;

       return true;

}

int main()

{

       int n,i;   

       while (~scanf("%d",&n))

       {

                for (i=0;i<n;i++) scanf("%d%d%d%d",&b[i].x0,&b[i].y0,&b[i].x1,&b[i].y1);

                for (i=0;i<n;i++)

                  for (int j=i+1;j<n;j++)

                  {

                         arc[i<<1][j<<1]=arc[j<<1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x0,b[j].y0);

                         arc[i<<1][j<<1|1]=arc[j<<1|1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x1,b[j].y1);

                         arc[i<<1|1][j<<1]=arc[j<<1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x0,b[j].y0);

                         arc[i<<1|1][j<<1|1]=arc[j<<1|1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x1,b[j].y1);

                  }

                int l,r,mid;

                l=0,r=2*oo;

                while (r-l>1)

                {

                        mid=(r+l)/2; 

                        if (_2sat(n,mid)) l=mid;

                           else r=mid;

                }

                printf("%.2lf\n",sqrt(l)*0.5);

       }

       return 0;

}


Program-----vector存图..其他同上

 

 

#include<iostream>

#include<stdio.h>

#include<string.h>

#include<cmath>

#include<queue>

#include<stack>

#include<set>

#include<map>

#include<algorithm>

#define ll long long

#define oo 1000000007

#define pi acos(-1.0)

#define MAXN 205

using namespace std;

struct node

{

       int x0,y0,x1,y1;

}b[MAXN];

vector<int> T[MAXN];

int dfn[MAXN],low[MAXN],tp[MAXN],tpnum,DfsIndex,arc[MAXN][MAXN];

bool instack[MAXN];

stack<int>  mystack;

int dis(int x0,int y0,int x1,int y1)

{

       return (x0-x1)*(x0-x1)+(y0-y1)*(y0-y1);

}

void tarjan(int x)  

{  

       int i,y,m=T[x].size();  

       dfn[x]=low[x]=++DfsIndex;  

       instack[x]=true;  

       mystack.push(x);  

       for (i=0;i<m;i++)  

       {  

              y=T[x][i];  

              if (!dfn[y])  

              {  

                  tarjan(y);  

                  low[x]=min(low[x],low[y]);  

              }else   

                  if (instack[y]) low[x]=min(low[x],dfn[y]);  

       }  

       if (dfn[x]==low[x])  

       {  

              tpnum++;  

              do  

              {  

                    x=mystack.top();  

                    mystack.pop();  

                    instack[x]=false;  

                    tp[x]=tpnum;  

              }while (dfn[x]!=low[x]);  

       }  

       return;  

}  

bool _2sat(int n,int d)

{

       int i,j;

       for (i=0;i<(n<<1);i++) T[i].clear(); //小错误..搞了N久才发现.. 

       for (i=0;i<n;i++)

          for (j=i+1;j<n;j++)

          {   

                  if (arc[i<<1][j<<1]<d)

                      T[i<<1].push_back(j<<1|1),T[j<<1].push_back(i<<1|1);

                  if (arc[i<<1][j<<1|1]<d)

                      T[i<<1].push_back(j<<1),T[(j<<1)|1].push_back(i<<1|1);

                  if (arc[i<<1|1][j<<1]<d)

                      T[(i<<1)|1].push_back((j<<1)|1),T[j<<1].push_back(i<<1);

                  if (arc[i<<1|1][j<<1|1]<d)

                      T[(i<<1)|1].push_back(j<<1),T[(j<<1)|1].push_back(i<<1);

          }

       memset(dfn,0,sizeof(dfn));

       memset(instack,false,sizeof(instack));

       while (!mystack.empty()) mystack.pop();

       tpnum=DfsIndex=0;

       for (i=0;i<(n<<1);i++)

           if (!dfn[i]) tarjan(i);

       for (i=0;i<n;i++)

           if (tp[i<<1]==tp[i<<1|1]) return false;

       return true;

}

int main()

{

       int n,i; 

       while (~scanf("%d",&n))

       {

                for (i=0;i<n;i++) scanf("%d%d%d%d",&b[i].x0,&b[i].y0,&b[i].x1,&b[i].y1);

                for (i=0;i<n;i++)

                  for (int j=i+1;j<n;j++)

                  {

                         arc[i<<1][j<<1]=arc[j<<1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x0,b[j].y0);

                         arc[i<<1][j<<1|1]=arc[j<<1|1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x1,b[j].y1);

                         arc[i<<1|1][j<<1]=arc[j<<1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x0,b[j].y0);

                         arc[i<<1|1][j<<1|1]=arc[j<<1|1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x1,b[j].y1);

                  }

                int l,r,mid;

                l=0,r=2*oo;

                while (r-l>1)

                {

                       mid=(r+l)>>1; 

                       if (_2sat(n,mid)) l=mid;

                           else r=mid;

                }

                printf("%.2f\n",sqrt(l)*0.5);

       }

       return 0;

}


Program-----vector存图..直接浮点进行运算...

 

 

#include<iostream>

#include<stdio.h>

#include<string.h>

#include<cmath>

#include<queue>

#include<stack>

#include<set>

#include<map>

#include<algorithm>

#define ll long long

#define eps 1e-5

#define oo 1000000007

#define pi acos(-1.0)

#define MAXN 205

using namespace std;

struct node

{

       int x0,y0,x1,y1;

}b[MAXN];

vector<int> T[MAXN];

int dfn[MAXN],low[MAXN],tp[MAXN],tpnum,DfsIndex;

double arc[MAXN][MAXN];

bool instack[MAXN];

stack<int>  mystack;

double dis(int x0,int y0,int x1,int y1)

{

       return sqrt((x0-x1)*(x0-x1)+(y0-y1)*(y0-y1));

}

void tarjan(int x)  

{  

       int i,y,m=T[x].size();  

       dfn[x]=low[x]=++DfsIndex;  

       instack[x]=true;  

       mystack.push(x);  

       for (i=0;i<m;i++)  

       {  

              y=T[x][i];  

              if (!dfn[y])  

              {  

                  tarjan(y);  

                  low[x]=min(low[x],low[y]);  

              }else   

                  if (instack[y]) low[x]=min(low[x],dfn[y]);  

       }  

       if (dfn[x]==low[x])  

       {  

              tpnum++;  

              do  

              {  

                    x=mystack.top();  

                    mystack.pop();  

                    instack[x]=false;  

                    tp[x]=tpnum;  

              }while (dfn[x]!=low[x]);  

       }  

       return;  

}  

bool _2sat(int n,double d)

{

       int i,j;

       for (i=0;i<(n<<1);i++) T[i].clear();

       for (i=0;i<n;i++)

          for (j=i+1;j<n;j++)

          {   

                  if (arc[i<<1][j<<1]+eps<d)

                      T[i<<1].push_back(j<<1|1),T[j<<1].push_back(i<<1|1);

                  if (arc[i<<1][j<<1|1]+eps<d)

                      T[i<<1].push_back(j<<1),T[(j<<1)|1].push_back(i<<1|1);

                  if (arc[i<<1|1][j<<1]+eps<d)

                      T[(i<<1)|1].push_back((j<<1)|1),T[j<<1].push_back(i<<1);

                  if (arc[i<<1|1][j<<1|1]+eps<d)

                      T[(i<<1)|1].push_back(j<<1),T[(j<<1)|1].push_back(i<<1);

          }

       memset(dfn,0,sizeof(dfn));

       memset(instack,false,sizeof(instack));

       while (!mystack.empty()) mystack.pop();

       tpnum=DfsIndex=0;

       for (i=0;i<(n<<1);i++)

           if (!dfn[i]) tarjan(i);

       for (i=0;i<n;i++)

           if (tp[i<<1]==tp[i<<1|1]) return false;

       return true;

}

int main()

{

       int n,i;  

       while (~scanf("%d",&n))

       {

                for (i=0;i<n;i++) scanf("%d%d%d%d",&b[i].x0,&b[i].y0,&b[i].x1,&b[i].y1);

                for (i=0;i<n;i++)

                  for (int j=i+1;j<n;j++)

                  {

                         arc[i<<1][j<<1]=arc[j<<1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x0,b[j].y0);

                         arc[i<<1][j<<1|1]=arc[j<<1|1][i<<1]=dis(b[i].x0,b[i].y0,b[j].x1,b[j].y1);

                         arc[i<<1|1][j<<1]=arc[j<<1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x0,b[j].y0);

                         arc[i<<1|1][j<<1|1]=arc[j<<1|1][i<<1|1]=dis(b[i].x1,b[i].y1,b[j].x1,b[j].y1);

                  }

                double l,r,mid;

                l=0,r=2*oo;

                while (r-l>eps)

                {

                        mid=(r+l)/2; 

                        if (_2sat(n,mid)) l=mid;

                           else r=mid;

                }

                printf("%.2lf\n",l*0.5);

       }

       return 0;

}


 



 

你可能感兴趣的:(game)