题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1676
题意:给出一个无向图,每个边有权值w,起点s和终点t。找出一个割集S,使得sigama(w)/|S|最小?
思路:二分答案x,则每条边的权值为w'=w-x,求最大流。最大流大于等于0,则说明x偏小。否则偏大。另外,对于w'为负的边,直接加入答案。最后从源点DFS一次。
#include <iostream>
#include <cstdio>
#include <string.h>
#include <algorithm>
#include <cmath>
#include <vector>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <map>
#define max(x,y) ((x)>(y)?(x):(y))
#define min(x,y) ((x)<(y)?(x):(y))
#define abs(x) ((x)>=0?(x):-(x))
#define i64 long long
#define u32 unsigned int
#define u64 unsigned long long
#define clr(x,y) memset(x,y,sizeof(x))
#define CLR(x) x.clear()
#define ph(x) push(x)
#define pb(x) push_back(x)
#define Len(x) x.length()
#define SZ(x) x.size()
#define PI acos(-1.0)
#define sqr(x) ((x)*(x))
#define MP(x,y) make_pair(x,y)
#define EPS 1e-5
#define FOR0(i,x) for(i=0;i<x;i++)
#define FOR1(i,x) for(i=1;i<=x;i++)
#define FOR(i,a,b) for(i=a;i<=b;i++)
#define FORL0(i,a) for(i=a;i>=0;i--)
#define FORL1(i,a) for(i=a;i>=1;i--)
#define FORL(i,a,b)for(i=a;i>=b;i--)
using namespace std;
void RD(int &x){scanf("%d",&x);}
void RD(u32 &x){scanf("%u",&x);}
void RD(double &x){scanf("%lf",&x);}
void RD(int &x,int &y){scanf("%d%d",&x,&y);}
void RD(u32 &x,u32 &y){scanf("%u%u",&x,&y);}
void RD(double &x,double &y){scanf("%lf%lf",&x,&y);}
void RD(int &x,int &y,int &z){scanf("%d%d%d",&x,&y,&z);}
void RD(int &x,int &y,int &z,int &t){scanf("%d%d%d%d",&x,&y,&z,&t);}
void RD(u32 &x,u32 &y,u32 &z){scanf("%u%u%u",&x,&y,&z);}
void RD(double &x,double &y,double &z){scanf("%lf%lf%lf",&x,&y,&z);}
void RD(char &x){x=getchar();}
void RD(char *s){scanf("%s",s);}
void RD(string &s){cin>>s;}
void PR(int x) {printf("%d\n",x);}
void PR(int x,int y) {printf("%d %d\n",x,y);}
void PR(i64 x) {printf("%lld\n",x);}
void PR(u32 x) {printf("%u\n",x);}
void PR(double x) {printf("%.5lf\n",x);}
void PR(char x) {printf("%c\n",x);}
void PR(char *x) {printf("%s\n",x);}
void PR(string x) {cout<<x<<endl;}
const int INF=1000000000;
const int N=100005;
struct Node
{
int v,next;
double cap,flow;
};
Node edges[N];
int n,m,s,t,head[N],e;
int num[N],h[N],curedge[N],pre[N];
void add(int u,int v,double cap)
{
edges[e].v=v;
edges[e].cap=cap;
edges[e].flow=0;
edges[e].next=head[u];
head[u]=e++;
}
void Add(int u,int v,double cap)
{
add(u,v,cap);
add(v,u,0);
}
double Maxflow(int s,int t,int n)
{
double ans=0.0,d;
int i,k,x,u;
memset(num,0,sizeof(num));
memset(h,0,sizeof(h));
for(i=0;i<=n;i++) curedge[i]=head[i];
num[n]=n;u=s;
while(h[u]<n)
{
if(u==t)
{
d=INF+1;
for(i=s;i!=t;i=edges[curedge[i]].v) if(d>edges[curedge[i]].cap)
k=i,d=edges[curedge[i]].cap;
for(i=s;i!=t;i=edges[curedge[i]].v)
{
x=curedge[i];
edges[x].cap-=d;
edges[x].flow+=d;
edges[x^1].cap+=d;
edges[x^1].flow-=d;
}
ans+=d;u=k;
}
for(i=curedge[u];i!=-1;i=edges[i].next) if(edges[i].cap>0&&h[u]==h[edges[i].v]+1)
break;
if(i!=-1)
{
curedge[u]=i;
pre[edges[i].v]=u;
u=edges[i].v;
}
else
{
if(--num[h[u]]==0) break;
curedge[u]=head[u];
for(x=n,i=head[u];i!=-1;i=edges[i].next) if(edges[i].cap>0&&h[edges[i].v]<x)
x=h[edges[i].v];
h[u]=x+1;num[h[u]]++;
if(u!=s) u=pre[u];
}
}
return ans;
}
int visit[10005],a[405],b[405];
double c[405];
int OK(double mid)
{
clr(head,-1); e=0;
double sum=0.0;
int i;
s=1,t=n;
FOR1(i,m)
{
if(c[i]<=mid) sum+=c[i]-mid;
else
{
Add(a[i],b[i],c[i]-mid);
Add(b[i],a[i],c[i]-mid);
}
}
sum+=Maxflow(s,t,t);
return sum>=0;
}
void DFS(int u)
{
visit[u]=1;
for(int i=head[u];i!=-1;i=edges[i].next)
{
if(visit[edges[i].v]||edges[i].cap<=0) continue;
DFS(edges[i].v);
}
}
int main()
{
while(scanf("%d%d",&n,&m)!=-1)
{
int i;
double low=INF,high=1.0,mid;
FOR1(i,m)
{
RD(a[i],b[i]); RD(c[i]);
low=min(low,c[i]);
high=max(high,c[i]);
}
while(high-low>EPS)
{
mid=(low+high)/2;
if(OK(mid)) low=mid;
else high=mid;
}
clr(visit,0); DFS(1);
int ans=0;
for(i=1;i<=m;i++) if(c[i]<=mid||visit[a[i]]+visit[b[i]]==1)
{
ans++;
}
PR(ans);
int flag=0;
for(i=1;i<=m;i++) if(c[i]<=mid||visit[a[i]]+visit[b[i]]==1)
{
if(flag) putchar(' ');
else flag=1;
printf("%d",i);
}
puts("");
}
return 0;
}