poj1003

                                                                                                          Hangover

Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 99369		Accepted: 48162

Description

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.

Input

The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

Output

For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Sample Input

1.00

3.71

0.04

5.19

0.00

Sample Output

3 card(s)

61 card(s)

1 card(s)

273 card(s)

Source

Mid-Central USA 2001

 1 #include<iostream>

 2 using namespace std;

 3 

 4 int main()

 5 {

 6     double sum = 0.5;

 7     double num[301]={0,0.5};

 8 

 9     for(int i=2;sum<=5.20;i++)

10     {

11         sum = sum + 1.0/(i+1) ;

12         num[i] = sum;

13     }

14     double n;

15     while(cin>>n)

16     {

17         if(n==0.00)

18             break;

19         for(int i=1;i<301;i++)

20         {

21             if(num[i]>=n)

22             {

23                 cout<<i<<" card(s)"<<endl;

24                 break;

25             }

26         }

27     }

28     return 0;

29 }