poj2394

最短路,有重边

View Code
#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
#include
<algorithm>
using namespace std;

#define INF 0x3f3f3f3f
#define N 505

int path[N], vis[N];
int n, m, c, p;
int lowcost[N];
int cost[N][N];
int cow[N];
int ans[N];

void Dijkstra()
{
int i, j, min;
memset(vis,
0, sizeof(vis));
int beg = 0;
vis[beg]
= 1;
for (i = 0; i < n; i++)
{
lowcost[i]
= cost[beg][i];
path[i]
= beg;
}
lowcost[beg]
= 0;
path[beg]
= -1;
int pre = beg;
for (i = 1; i < n; i++)
{
min
= INF;
for (j =0; j < n; j++)
if (vis[j] == 0 && lowcost[pre] + cost[pre][j] <lowcost[j])
{
lowcost[j]
= lowcost[pre] + cost[pre][j];
path[j]
= pre;
}
for (j = 0; j < n; j++)
if (vis[j] == 0 && lowcost[j] < min)
{
min
= lowcost[j];
pre
= j;
}
vis[pre]
= 1;
}
}

int main()
{
//freopen("t.txt", "r", stdin);
scanf("%d%d%d%d", &n, &m, &c, &p);
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
cost[i][j]
= INF;
for (int i = 0; i < n; i++)
cost[i][i]
= 0;
for (int i = 0; i < m; i++)
{
int a, b, x;
scanf(
"%d%d%d", &a, &b, &x);
a
--;
b
--;
cost[a][b]
= cost[b][a] = min(x, cost[a][b]);
}
for (int i = 0; i < c; i++)
scanf(
"%d", &cow[i]);
Dijkstra();
int tot = 0;
for (int i = 0; i < c; i++)
if (lowcost[cow[i] - 1] <= p)
ans[tot
++] = i;
sort(ans, ans
+ tot);
printf(
"%d\n", tot);
for (int i = 0; i < tot; i++)
printf(
"%d\n", ans[i] + 1);
return 0;
}

你可能感兴趣的:(poj)