一道c++小编程题，
题目:
编写一个小程序,从标准输入读入一系列string对象,寻找连续重复出现的单词,程序应该找出满足以下条件的单词的输入位置:该单词的后面紧跟着再次出现自己本身,跟 踪重复次数量多的单词及其重复次数.输出重复次数的最大值,
例如.如果输入是:
how now now now brown cow cow
则输出表明now这个单词出现了三次
本人解法：
#include <iostream>
#include <string>
#include <cctype>
#include <vector>
using namespace std;
int main() {
string s;
vector<string> vec;
int maxRepeat = 0;
while (cin >> s){
if(ispunct(s[s.size()-1])) s = s.substr(0,s.size() - 1); //去除最后的标点符号
vec.push_back(s);
}
vector<string>::size_type i = 0;
vector<int> vecInt(vec.size(),1);
while (i != vec.size() - 1){
int j = i;
string str = vec[i];
while(i != vec.size() - 1)
{
if(str == vec[++i]) vecInt[j] ++;
else break;
}
}
vector<int>::size_type k = 0;
int max = vecInt[k];
int flag = 0;
while (k != vecInt.size() - 1){
if(max < vecInt[++k]){
max = vecInt[k];
flag = k;
}
}
cout << "The word of " << vec[flag] << " repeats: " << vecInt[flag] << " times." << endl;
cout << endl;
return 0; }
自己的解法答案是对的 但从空间复杂度来说要复杂的多，所以在网上搜了下，寻找到另外一种解决办法，修改后的代码如下:
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
int main() {
string nowWord,beforeWord,result;
cin >> nowWord;
if(ispunct(nowWord[nowWord.size() - 1]))nowWord = nowWord.substr(0,nowWord.size() - 1);
result = beforeWord = nowWord;
int count = 1,maxCount = 1;
while(cin >> nowWord){
if(ispunct(nowWord[nowWord.size() - 1]))nowWord = nowWord.substr(0,nowWord.size() - 1);
if (beforeWord == nowWord){
count++;
}
else{
beforeWord = nowWord;
count = 1;
}
if(count > maxCount){
maxCount = count;
result = nowWord;
}
}
if(maxCount == 1) cout << "There is no word repeating." << endl;
else cout << "The word of " << result << " repeats: " << maxCount << " times." << endl;
return 0;
}
特在此分享给大家 参考或给予好的想法参考改进。。谢谢~~