测试一字符串在另一字符串中出现的次数，Character的运用

 

public   static   void  test1() {
        String s="AaaaABBBBcc&^%adfsfdCCOOkk99876 _haHA";
        int lCount=0,uCount=0,oCount=0,nCount=0;
        for(int i=0;i<s.length();i++)
        {
            char c=s.charAt(i);
//            if(c>='a'&&c<='z')
//            {
//                lCount++;
//            }else if(c>='A'&&c<='Z')
//            {
//                uCount++;
//            }
//            else
//            {
//                oCount++;
//            }
            if(Character.isLowerCase(c))
            {
                lCount++;
            }else if(Character.isUpperCase(c))
            {
                uCount++;
            }
            else if(Character.isDigit(c))
            {
                nCount++;
            }else
            {
                oCount++;
            }
                 
        }
        System.out.println(lCount+"  "+uCount+"  "+nCount+"  "+oCount);
    }
     public   static   void  test2() {
        int count=0,index=-1;
        String s = "sunjavahpjavaokjavajjavahahajavajavagoodjava";
        String sFind="java";
        while((index=s.indexOf(sFind))!=-1)
        {
            s=s.substring(index+sFind.length());
            count++;
        }
        System.out.println(count);

    }