hibernate里的级联条件查询

public int getCount(long user, long project, long type, String  simNumber,
   String callBarring, String puk, String local) {

  Criteria criteria = session.createCriteria(Sim.class);
  if (user != 0) {
   criteria.add(Restrictions.eq("user.id", user));
  }
  if (project != 0) {
   Restrictions.eq("project.id", project);
  }
  if (type != 0) {
   criteria.add(Restrictions.eq("type.id", type));
  }
  if (!"".equals(simNumber) && simNumber != null) {
   criteria.add(Restrictions.like("simNumber", "%" + simNumber + "%"));
  }
  if (!"".equals(callBarring) && callBarring != null) {
   criteria.add(Restrictions.eq("callBarring", callBarring));
  }

  if (!"".equals(puk) && puk != null) {
   criteria.add(Restrictions.like("puk", "%" + puk + "%"));
  }
  if (!"".equals(local) && local != null) {
   criteria.createCriteria("user").add(Restrictions.eq("local", local));
  }

  criteria.setProjection(Projections.rowCount());
  return (Integer) criteria.uniqueResult();
 }

 

 

今天发现的：hibernate里的 criteria.add(Restrictions.eq("*", *));

是有选择的，我的Book对象里的user(对象).id  type(对象).id 可以，id是long型。

  criteria.add(Restrictions.eq("type.id", type));

但是，遇到String类型的local就不行了。只能
criteria.createCriteria("user").add(Restrictions.eq("local", local));