hdu3079――Vowel Counting

原题：

Problem Description

The "Vowel-Counting-Word"(VCW), complies with the following conditions.
Each vowel in the word must be uppercase.
Each consonant (the letters except the vowels) must be lowercase.
For example, "ApplE" is the VCW of "aPPle", "jUhUA" is the VCW of "Juhua".
Give you some words; your task is to get the "Vowel-Counting-Word" of each word.

 

 

Input

The first line of the input contains an integer T (T<=20) which means the number of test cases.
For each case, there is a line contains the word (only contains uppercase and lowercase). The length of the word is not greater than 50.

 

 

Output

For each case, output its Vowel-Counting-Word.

 

 

Sample Input

   
   
   
   

    
    
    
    4 XYz application qwcvb aeioOa  
   
   
   
   

 

 

Sample Output

   
   
   
   

    
    
    
    xyz ApplIcAtIOn qwcvb AEIOOA 
   
   
   
   

分析：

元音――>大写；；；；；辅音――>小写

原码：

#include<iostream> #include<string.h> #include<ctype.h> #include<stdio.h> using namespace std; int main() {     int n,l,i;     char s[66];     scanf("%d",&n);     while(n--)     {         getchar();         scanf("%s",s);         l=strlen(s);         for(i=0; i<l; i++)         {             if(s[i]>='A'&&s[i]<='Z')             {                 if(s[i]=='A'||s[i]=='I'||s[i]=='E'||s[i]=='O'||s[i]=='U')                     printf("%c",s[i]);                 else printf("%c",tolower(s[i]));             }             else             {                 if(s[i]=='a'||s[i]=='i'||s[i]=='o'||s[i]=='u'||s[i]=='e')printf("%c",toupper(s[i]));                 else                     printf("%c",s[i]);             }         }         printf("\n");     }     return 0; }