迷宫的第二种写法――递归实现

package com.java.study;
class MazeClass{
    private int []H = {0 ,1 ,0, -1};
    private int []V = {-1 ,0 ,1, 0};//上，右，下，左
    private char[][]Maze;
    private int len;
    public MazeClass(char[][]Maze, int len){
        this.Maze = Maze;
        this.len = len;
    }
    public void FindPath(int x, int y){
        if(x==len || y==len){
            for(int i = 0 ; i < len ;i++){
                for(int j = 0 ; j < len; j++){
                    char fenge = j < len-1 ? ' ':'\n';
                    System.out.print(Maze[i][j]);
                    System.out.print(fenge);
                }
            }
        }else for(int k = 0 ; k < 4; k++){
            if(x>=0 && y>=0 && y<len && x<len && 'o'==Maze[x][y]){
                Maze[x][y] = ' ';
                FindPath(x+V[k] , y+H[k]);//按四个方向去搜
                Maze[x][y] = 'o';
            }
        }
    }
}
public class Maze {
      
    public static void main(String[] args) {
        char Maze[][] =
                {{'X','X','X','X','X','X','X','X'},
                {'o','o','o','o','o','X','X','X'},
                {'X','o','X','X','o','o','o','X'},
                {'X','o','X','X','o','X','X','o'},
                {'X','o','X','X','X','X','X','X'},
                {'X','o','X','X','o','o','o','X'},
                {'X','o','o','o','o','X','o','o'},
                {'X','X','X','X','X','X','X','X'}};
        MazeClass mc = new MazeClass(Maze,Maze.length);
        mc.FindPath(1, 0);
    }
}