google map根据地址获取经纬度

最近在做google map 根据地址获取经纬度的时候使用到Geocoder类

 

Java 代码复制内容到剪贴板

/**
     * 将地址转为经纬度
     * @param address
     * @return
     */
    public GeoPoint getGeoPointByAddress(String address) {
        GeoPoint geoPoint = null;
        if (address != "") {
            Geocoder myGeocoder = new Geocoder(RegisterAccountActivity.this);
            List<Address> addressList = null;
            try {
                addressList = myGeocoder.getFromLocationName(address, 1);
                if (!addressList.isEmpty()) {
                    Address tempAddress = addressList.get(0);
                    double myLatitude = tempAddress.getLatitude() * 1E6;
                    double myLongitude = tempAddress.getLongitude() * 1E6;
                    geoPoint = new GeoPoint((int) myLatitude, (int) myLongitude);
                }
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
        return geoPoint;
    }

这段代码对2.2和2.3系统居然不起作用，报java.io.IOException: Service not Available的错误，换用2.1系统却可以。

估计这是个bug。于是在网上找到另一种解决方法：

 

Java 代码复制内容到剪贴板

public static JSONObject getLocationInfo(String address) {

        HttpGet httpGet = new HttpGet(
                "http://maps.g...ddress="
                        + address + "ka&sensor=false");
        HttpClient client = new DefaultHttpClient();
        HttpResponse response;
        StringBuilder stringBuilder = new StringBuilder();

        try {
            response = client.execute(httpGet);
            HttpEntity entity = response.getEntity();
            InputStream stream = entity.getContent();
            int b;
            while ((b = stream.read()) != -1) {
                stringBuilder.append((char) b);
            }
        } catch (ClientProtocolException e) {
        } catch (IOException e) {
        }

        JSONObject jsonObject = new JSONObject();
        try {
            jsonObject = new JSONObject(stringBuilder.toString());
        } catch (JSONException e) {
            e.printStackTrace();
        }
        return jsonObject;
    }

    public static GeoPoint getGeoPoint(JSONObject jsonObject) {
        Double lon = new Double(0);
        Double lat = new Double(0);
        try {
            lon = ((JSONArray) jsonObject.get("results")).getJSONObject(0)
                    .getJSONObject("geometry").getJSONObject("location")
                    .getDouble("lng");

            lat = ((JSONArray) jsonObject.get("results")).getJSONObject(0)
                    .getJSONObject("geometry").getJSONObject("location")
                    .getDouble("lat");

        } catch (JSONException e) {
            e.printStackTrace();
        }
        return new GeoPoint((int) (lat * 1E6), (int) (lon * 1E6));
    }

这样就解决了问题。