SQL字符串转换为数组
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一、按指定符号分割字符串，返回分割后的元素个数，方法很简单，就是看字符串中存在多少个分隔符号，然后再加一，就是要求的结果。
-----rtrim(@str)去掉 @str右边的字符 ltrim(@str)去掉左边的字符 ltrim(rtrim(@str))去掉左右空格
-------charindex 在变量@str中@split的index即索引值
create function Get_StrArrayLength ( @str varchar(5000), --要分割的字符串 @split varchar(10) --分隔符号)returns intasbegin declare @location int declare @start int declare @length int set @str=ltrim(rtrim(@str)) set @location=charindex(@split,@str) set @length=1 while @location<>0 begin set @start=@location+1 set @location=charindex(@split,@str,@start) set @length=@length+1 end return @lengthend
二、按指定符号分割字符串，返回分割后指定索引的第几个元素，象数组一样方便
create function Get_StrArrayStrOfIndex ( @str varchar(5000), --要分割的字符串 @split varchar(10), --分隔符号 @index int --取第几个元素)returns varchar(5000)asbegin declare @location int declare @start int declare @next int declare @seed int set @str=ltrim(rtrim(@str)) set @start=1 set @next=1 set @seed=len(@split) set @location=charindex(@split,@str) while @location<>0 and @index>@next begin set @start=@location+@seed set @location=charindex(@split,@str,@start) set @next=@next+1 end if @location =0 select @location =len(@str)+1 return substring(@str,@start,@location-@start)end
调用示例
--==================================declare @str varchar(5000)set @str='1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48'print dbo.Get_StrArrayLength(@str,',')declare @next int declare @s varchar(100) set @next=1while @next<=dbo.Get_StrArrayLength(@str,',')begin print dbo.Get_StrArrayStrOfIndex(@str,',',@next) ----输出数组中的值 set @next=@next+1end--==================================
四、检查一个元素是否在数组中
Create function CheckStrInArr(@s as varchar(50),@sArr as varchar(5000)) returns intas begindeclare @str varchar(5000)set @str=@sArrdeclare @next int declare @ret intset @ret=0set @next=1while @next<=dbo.Get_StrArrayLength(@str,',')begin
if dbo.Get_StrArrayStrOfIndex(@str,',',@next)=@s
begin
set @ret=1; end
set @next=@next+1endreturn @retend-- =========调用失利========declare @a intset @a=dbo.CheckStrInArr('8','2,3,5,8')select @a-- =========调用失利========
五 检查一个元素是否与数组中的相匹配
--select dbo.CheckStrLikeInArr(2,'d','sde,df,aad,d,fgsa,fgd')Create function CheckStrLikeInArr (@liketype int=0, --like类型(0为为@keyword%,2为) 一般只用0@keyword as varchar(50), --要检查的关键字@sArr as varchar(5000) --数组) returns nvarchar(max)as begindeclare @str varchar(5000) set @str=@sArrdeclare @start int declare @result nvarchar(max) set @result='' set @start=1declare @temp nvarchar(20);while @start<=dbo.Get_StrArrayLength(@str,',')begin if @liketype=0 begin set @temp=dbo.Get_StrArrayStrOfIndex(@str,',',@start); if @temp like '%'+ @keyword+'%' begin set @result=@result+ @temp +','; end set @start=@start+1 end else if @liketype=1 begin if dbo.Get_StrArrayStrOfIndex(@str,',',@start) like ''+ @keyword +'%' begin set @result=dbo.Get_StrArrayStrOfIndex(@str, ',' , @start)+','; end set @start=@start+1 end else if @liketype=2 begin if dbo.Get_StrArrayStrOfIndex( @str, ',' , @start) like '%'+ @keyword+'' begin set @result=dbo.Get_StrArrayStrOfIndex(@str, ',' , @start)+','; end set @start=@start+1 endendreturn @result-- return cast(dbo.Get_StrArrayLength(@result,',')as nvarchar(2000)) end