myeclipse--注册码破解

在安装myeclipse之后，进入后系统会让我们录入注册码。

多了不说，下面这段代码执行下，在console上会给出一段密码，自己试试吧，很好用。

import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar;

/**
 * myeclipse blue 7.5 keygen
 * 
 * @author Administrator
 * 
 */
public class t {
	public static final void main(String[] args) {
		String id = "zzq"; // 可更给为您的名字
		String num = "999";// 许可证数量
		System.out.println(getSerial(id, "100", num, true));
	}

	public static String getSerial(String userId, String version,
			String licenseNum, boolean selected) {
		Calendar cal = Calendar.getInstance();
		cal.add(1, 3);
		cal.add(6, -1);
		NumberFormat nf = new DecimalFormat("000");
		licenseNum = nf.format(Integer.valueOf(licenseNum));
		String verTime = selected ? (new StringBuffer("-")).append(
				(new SimpleDateFormat("yyMMdd")).format(cal.getTime())).append(
				"0").toString() : "-1012310";
		String type = "YE3MB-";
		String need = (new StringBuffer(String.valueOf(userId.substring(0, 1))))
				.append(type).append(version).append(licenseNum)
				.append(verTime).toString();
		String dx = (new StringBuffer(String.valueOf(need)))
				.append(
						"Decompiling this copyrighted software is a violation of both your license agreement and the Digital Millenium Copyright Act of 1998 (http://www.loc.gov/copyright/legislation/dmca.pdf). Under section 1204 of the DMCA, penalties range up to a $500,000 fine or up to five years imprisonment for a first offense. Think about it; pay for a license, avoid prosecution, and feel better about yourself.")
				.append(userId).toString();
		int suf = decode(dx);
		String code = (new StringBuffer(String.valueOf(need))).append(
				String.valueOf(suf)).toString();
		return change(code);
	}

	private static int decode(String s) {
		int i = 0;
		char ac[] = s.toCharArray();
		int j = 0;
		for (int k = ac.length; j < k; j++)
			i = 31 * i + ac[j];
		return Math.abs(i);
	}

	private static String change(String s) {
		byte abyte0[] = s.getBytes();
		char ac[] = new char[s.length()];
		int i = 0;
		for (int k = abyte0.length; i < k; i++) {
			int j = abyte0[i];
			if (j >= 48 && j <= 57)
				j = ((j - 48) + 5) % 10 + 48;
			else if (j >= 65 && j <= 90)
				j = ((j - 65) + 13) % 26 + 65;
			else if (j >= 97 && j <= 122)
				j = ((j - 97) + 13) % 26 + 97;
			ac[i] = (char) j;
		}
		return String.valueOf(ac);
	}

}