利用switch语句解决问题：定期存款利息计算器

#include <stdio.h>
int main ( )
{
     int  type;
    double money, period, rate, interest;
    printf("欢迎使用利息计算器！\n");
    printf("请输入存款金额：");
    scanf("%lf", &money);
    printf("======存款期限======\n");
    printf("1. 3个月 \n");
    printf("2. 6个月\n");
    printf("3. 一年 \n");
    printf("4. 二年\n");
    printf("5. 三年\n");
    printf("6. 五年\n");
    printf("请输入存款期限的代号：");
    scanf("%d", &type);
    if (type>=1 && type <=6)
    {
        switch(type)   //在if中嵌入了switch分情况处理
        {
        case 1:
            period = 0.25;
            rate = 0.031;
            break;
        case 2:
            period = 0.5;
            rate = 0.033;
            break;
        case 3:
            period = 1;
            rate = 0.035;
            break;
        case 4:
            period = 2;
            rate = 0.044;
            break;
        case 5:
            period = 3;
            rate = 0.05;
            break;
        case 6:
            period = 5;
            rate = 0.055;
            break;
        }
        interest = money * period * rate;
        printf("到期利息为：%.2lf 元，本息合计共 %.2lf 元。\n", interest, interest + money);
    }
    else
        printf("选择存款类型错误！\n");
    printf("感谢您的使用，欢迎下次光临！\n");
    return 0;
}