高精度运算（运算符重载）

终于写好了哇，我的亲娘来，满满的都是泪啊。。。重载你妹啊。。。。。

#include <iostream>
#include <string.h>
using namespace std;
const int Base=1000000000;
const int Capacity=100;
typedef long long huge;

struct BigInt
{
    int Len;
    int Data[Capacity];
    BigInt() : Len(0) {}
    BigInt (const BigInt &V) : Len(V.Len)
    {
        memcpy (Data, V.Data, Len*sizeof*Data);
    }
    BigInt(int V) : Len(0)
    {
        for(; V>0; V/=Base) Data[Len++]=V%Base;
    }
    BigInt &operator=(const BigInt &V)
    {
        Len=V.Len;
        memcpy(Data, V.Data, Len*sizeof*Data);
        return *this;
    }
    int &operator[] (int Index)
    {
        return Data[Index];
    }
    int operator[] (int Index) const
    {
        return Data[Index];
    }
};
int compare(const BigInt &A, const BigInt &B)
{
    if(A.Len!=B.Len) return A.Len>B.Len ? 1:-1;
    int i;
    for(i=A.Len-1; i>=0 && A[i]==B[i]; i--);
    if(i<0)return 0;
    return A[i]>B[i] ? 1:-1;
}

BigInt operator + (const BigInt &A,const BigInt &B)
{
    int i,Carry(0);
    BigInt R;
    for(i=0; i<A.Len||i<B.Len||Carry>0; i++)
    {
        if(i<A.Len) Carry+=A[i];
        if(i<B.Len) Carry+=B[i];
        R[i]=Carry%Base;
        Carry/=Base;
    }
    R.Len=i;
    return R;
}

BigInt operator - (const BigInt &A,const BigInt &B)
{
    int i,Carry(0);
    BigInt R;
    R.Len=A.Len;
    for(i=0; i<R.Len; i++)
    {
        R[i]=A[i]-Carry;
        if(i<B.Len) R[i]-=B[i];
        if(R[i]<0) Carry=1,R[i]+=Base;
        else Carry=0;
    }
    while(R.Len>0&&R[R.Len-1]==0) R.Len--;
    return R;
}

BigInt operator * (const BigInt &A,const BigInt &B)
{
    int i;
    huge Carry(0);
    BigInt R;
    for(i=0; i<A.Len||Carry>0; i++)
    {
        if(i<A.Len) Carry+=huge(A[i])*B[i];
        R[i]=Carry%Base;
        Carry/=Base;
    }
    R.Len=i;
    return R;
}
istream &operator>>(istream &In,BigInt &V)
{
    char Ch;
    for(V=0; In>>Ch;)
    {
        V=V*10+(Ch-'0');
        if(In.peek()<=' ') break;
    }
    return In;
}
ostream &operator<<(ostream &Out,const BigInt &V)
{
    int i;
    Out<<(V.Len==0 ? 0:V[V.Len-1]);
    for(i=V.Len-2; i>=0; i--) for(int j=Base/10; j>0; j/=10) Out<<V[i]/j;
    return Out;
}
int main()
{
    BigInt a,b;
    cin>>a>>b;
    cout<<"+"<<endl;
    cout<<a+b<<endl;
    if(compare(a, b)>0) cout<<"-"<<endl<<a-b<<endl;
    else cout<<"-"<<endl<<b-a<<endl;
    cout<<"*"<<endl<<a*b<<endl;
}

另一版本

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <limits>
#include <cstdlib>

using namespace std;

const int MAXD = 10000, DIG = 9, BASE = 1000000000;

const unsigned long long BOUND = numeric_limits <unsigned long long> :: max () - (unsigned long long) BASE * BASE;

class bignum
{
private:
    int digits[MAXD];
    int D;
public:

    friend ostream &operator<<(ostream &out,bignum &c);

    inline void trim()
    {
        while(D > 1 && digits[D-1] == 0 )
            D--;
    }

    inline void dealint(long long x)
    {
        memset(digits,0,sizeof(digits));
        D = 0;
        do
        {
            digits[D++] = x % BASE;
            x /= BASE;
        }
        while(x > 0);
    }

    inline void dealstr(char *s)
    {
        memset(digits,0,sizeof(digits));
        int len = strlen(s),first = (len + DIG -1)%DIG + 1;

        D = (len+DIG-1)/DIG;

        for(int i = 0; i < first; i++)
            digits[D-1] = digits[D-1]*10 + s[i] - '0';

        for(int i = first, d = D-2; i < len; i+=DIG,d--)
            for(int j = i; j < i+DIG; j++)
                digits[d] = digits[d]*10 + s[j]-'0';

        trim();
    }

    inline char *print()
    {
        trim();

        char *cdigits = new char[DIG * D + 1];

        int pos = 0,d = digits[D-1];

        do
        {
            cdigits[pos++] = d % 10 + '0';
            d/=10;
        }
        while(d > 0);

        reverse(cdigits,cdigits+pos);

        for(int i = D - 2; i >= 0; i--,pos += DIG)
            for(int j = DIG-1,t = digits[i]; j >= 0; j--)
            {
                cdigits[pos+j] = t%10 + '0';
                t /= 10;
            }

        cdigits[pos] = '\0';

        return cdigits;
    }


    bignum()
    {
        dealint(0);
    }

    bignum(long long x)
    {
        dealint(x);
    }

    bignum(int x)
    {
        dealint(x);
    }

    bignum(char *s)
    {
        dealstr(s);
    }



    inline bool operator < (const bignum &o) const
    {
        if(D != o.D)
            return D < o.D;

        for(int i = D-1; i>=0; i--)
            if(digits[i] != o.digits[i])
                return digits[i] < o.digits[i];
        return false; //equal

    }

    bool operator >  (const bignum & o)const
    {
        return o < *this;
    }
    bool operator <= (const bignum & o)const
    {
        return !(o < *this);
    }
    bool operator >= (const bignum & o)const
    {
        return !(*this < o);
    }
    bool operator != (const bignum & o)const
    {
        return o < *this || *this < o;
    }
    bool operator == (const bignum & o)const
    {
        return !(o < *this) && !(*this < o);
    }


    bignum &operator++()
    {
        *this = *this  + 1;
        return *this;
    }


    bignum operator ++(int)
    {
        bignum old = *this;
        ++(*this);
        return old;
    }

    inline bignum operator << (int p) const
    {
        bignum temp;
        temp.D = D + p;

        for (int i = 0; i < D; i++)
            temp.digits [i + p] = digits [i];

        for (int i = 0; i < p; i++)
            temp.digits [i] = 0;

        return temp;
    }

    inline bignum operator >> (int p) const
    {
        bignum temp;
        temp.D = D - p;

        for (int i = 0; i < D - p; i++)
            temp.digits [i] = digits [i + p];

        for (int i = D - p; i < D; i++)
            temp.digits [i] = 0;

        return temp;
    }


    bignum &operator += (const bignum &b)
    {
        *this = *this + b;
        return *this;
    }

    bignum &operator -= (const bignum &b)
    {
        *this = *this - b;
        return *this;
    }

    bignum &operator *= (const bignum &b)
    {
        *this = *this * b;
        return *this;
    }

    bignum &operator /= (const bignum &b)
    {
        *this = *this / b;
        return *this;
    }

    bignum &operator %= (const bignum &b)
    {
        *this = *this % b;
        return *this;
    }

    inline bignum operator + (const bignum &o) const
    {
        bignum sum = o;
        int carry = 0;

        for (sum.D = 0; sum.D < D || carry > 0; sum.D++)
        {
            sum.digits [sum.D] += (sum.D < D ? digits [sum.D] : 0) + carry;

            if (sum.digits [sum.D] >= BASE)
            {
                sum.digits [sum.D] -= BASE;
                carry = 1;
            }
            else
                carry = 0;
        }

        sum.D = max (sum.D, o.D);
        sum.trim ();
        return sum;
    }
    inline bignum operator - (const bignum &o) const
    {
        bignum diff = *this;

        for (int i = 0, carry = 0; i < o.D || carry > 0; i++)
        {
            diff.digits [i] -= (i < o.D ? o.digits [i] : 0) + carry;

            if (diff.digits [i] < 0)
            {
                diff.digits [i] += BASE;
                carry = 1;
            }
            else
                carry = 0;
        }

        diff.trim ();
        return diff;
    }
    inline bignum operator * (const bignum &o) const
    {
        bignum prod = 0;
        unsigned long long sum = 0, carry = 0;

        for (prod.D = 0; prod.D < D + o.D - 1 || carry > 0; prod.D++)
        {
            sum = carry % BASE;
            carry /= BASE;

            for (int j = max (prod.D - o.D + 1, 0); j <= min (D - 1, prod.D); j++)
            {
                sum += (unsigned long long) digits [j] * o.digits [prod.D - j];

                if (sum >= BOUND)
                {
                    carry += sum / BASE;
                    sum %= BASE;
                }
            }

            carry += sum / BASE;
            prod.digits [prod.D] = sum % BASE;
        }

        prod.trim ();
        return prod;
    }
    inline bignum range (int a, int b) const
    {
        bignum temp = 0;
        temp.D = b - a;

        for (int i = 0; i < temp.D; i++)
            temp.digits [i] = digits [i + a];

        return temp;
    }


    inline double double_div (const bignum &o) const
    {
        double val = 0, oval = 0;
        int num = 0, onum = 0;

        for (int i = D - 1; i >= max (D - 3, 0); i--, num++)
            val = val * BASE + digits [i];

        for (int i = o.D - 1; i >= max (o.D - 3, 0); i--, onum++)
            oval = oval * BASE + o.digits [i];

        return val / oval * (D - num > o.D - onum ? BASE : 1);
    }

    inline pair <bignum, bignum> divmod (const bignum &o) const
    {
        bignum quot = 0, rem = *this, temp;

        for (int i = D - o.D; i >= 0; i--)
        {
            temp = rem.range (i, rem.D);
            int div = (int) temp.double_div (o);
            bignum mult = o * div;

            while (div > 0 && temp < mult)
            {
                mult = mult - o;
                div--;
            }

            while (div + 1 < BASE && !(temp < mult + o))
            {
                mult = mult + o;
                div++;
            }

            rem = rem - (o * div << i);

            if (div > 0)
            {
                quot.digits [i] = div;
                quot.D = max (quot.D, i + 1);
            }
        }

        quot.trim ();
        rem.trim ();
        return make_pair (quot, rem);
    }

    inline bignum operator / (const bignum &o) const
    {
        return divmod (o).first;
    }

    inline bignum operator % (const bignum &o) const
    {
        return divmod (o).second;
    }


    inline bignum power (int exp) const
    {
        bignum p = 1, temp = *this;

        while (exp > 0)
        {
            if (exp & 1) p = p * temp;
            if (exp > 1) temp = temp * temp;
            exp >>= 1;
        }

        return p;
    }

    inline bignum factorial() const
    {
        bignum ans = 1, num = *this;

        if (num == 0 || num == 1)
            return ans;
        while (!(num < 0 || num == 0))
        {
            ans = ans * num;
            num = num - 1;
        }
        return ans;
    }
};

ostream &operator<<(ostream &out, bignum &c)
{
    out<<c.print();
    return out;
}

istream &operator >> (istream &in,bignum &c)
{
    char s[10000];
    in>>s;
    c = s;
    return in;
}
bignum gcd(bignum a,bignum b)
{
    return b==0?a:gcd(b,a%b);
}
bignum f[1800];

int main()
{

}