经典的打表 zoj 3193 Accurately Say "CocaCola"! Again

经典的打表 zoj 3193 Accurately Say "CocaCola"! Again

#include < stdio.h >
long  f(__int64 n)
{
    while(n!=0){
        if(n%10==7)return 1;
        n/=10;
    }
    return 0;
}
int  main()
{
    static __int64 a[1000000],n,m,i,j=0,f1;
    for(i=7;i<1000000000;i++){
        if(f(i)||i%7==0)
            a[j]++;
        else {
            f1=1;
            for(int k=0;k<j;k++)
                if(a[j]<=a[k])f1=0;
            if(f1){printf("p=%I64d,x=%I64d\n",a[j],i-a[j]);
                  j++;}
            else a[j]=0;
            
        }
    }
}

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=3318
比赛时没有想到，就是靠人脑举例，导致考虑不完整，出现很多错误！后来经高人指点，编学了个辅助程序，终于ac了！
O(∩_∩)O~，看来还是要好好利用电脑！！

主程序：

#include < stdio.h >
int  main()
{
    long n,t;
    scanf("%d",&t);
    while(t--){
        scanf("%d",&n);
        if(n==1)printf("7\n");
        else if(n==2)printf("27\n");
        else if(n<=10)printf("70\n");
        else if(n<=11)printf("270\n");
        else if(n<=100)printf("700\n");
        else if(n<=101)printf("2700\n");
        else if(n<=1000)printf("7000\n");
        else if(n<=1002)printf("26999\n");
        else if(n<=10000)printf("70000\n");
        else if(n<=10001)printf("270000\n");
        else if(n<=100000)printf("700000\n");
        else if(n<=100001)printf("1699999\n");
        else if(n<=1000000)printf("7000000\n");
        else if(n<=1000001)printf("27000000\n");
        else if(n<=10000000)printf("70000000\n");
        else if(n<=10000001)printf("270000000\n");
        else printf("700000000\n");
    }
}