STL algorithm算法copy(6)
std::copy
template <class InputIterator, class OutputIterator>
OutputIterator copy (InputIterator first, InputIterator last, OutputIterator result);
[first,last) into the range beginning at result.复制范围[first,last）里面的元素到result的位置。（将会覆盖原来的数据）
例子：
#include <iostream>
#include <algorithm>
#include <vector>
#include <array>
using namespace std;
void copy1(){
vector<int> v1{1,5,7,8,9};
vector<int> v2{100,200,300};
array<int,7> ai{888,666.555,222,111,555,777};
vector<double> vd{9.9,8.8,7.7,};
cout<<"at first,v1=";
for(int &i:v1)
cout<<i<<" ";
cout<<endl;
cout<<"at first,v2=";
for(int &i:v2)
cout<<i<<" ";
cout<<endl;
auto it=copy(v2.begin(),v2.end(),v1.begin());
cout<<"after copy(v2.begin(),v2.end(),v1.begin())"<<endl;
cout<<"v1=";
for(int &i:v1)
cout<<i<<" ";
cout<<endl;
cout<<"v2=";
for(int &i:v2)
cout<<i<<" ";
cout<<endl;
cout<<"the return it is :*it="<<*it<<endl;
}
运行截图：
The function returns an iterator to the end of the destination range (which points to the element following the last element copied).
该函数返回一个迭代器，指向目标范围的最后（即last的下一个元素）（上面例子的8）
The ranges shall not overlap in such a way that result points to an element in the range [first,last). For such cases, see copy_backward.
result不应该指向[first,last)中的任一元素，如果需要，应该使用copy_backward.（这句话很有问题，因为copy_backward也有一句几乎一样的话，具体需求请具体分析）
例子：
#include <iostream>
#include <algorithm>
#include <vector>
#include <array>
using namespace std;
void copy2(){
vector<int> v1{1,5,7,8,9};
cout<<"at first,v1=";
for(int &i:v1)
cout<<i<<" ";
cout<<endl;
auto it=copy(v1.begin(),v1.end(),v1.begin()+3);
cout<<"after copy(v1.begin(),v1.end(),v1.begin()+3)"<<endl;
cout<<"v1=";
for(int &i:v1)
cout<<i<<" ";
cout<<endl;
cout<<"the return it is :*it="<<*it<<endl;
}
运行截图：
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Parameters
- first, last
-
Input iterators to the initial and final positions in a sequence to be copied. The range used is
[first,last), which contains all the elements between first and last, including the element pointed by first but not the element pointed by last.
要复制的范围。 - result
-
Output iterator to the initial position in the destination sequence.
This shall not point to any element in the range[first,last).
要覆盖数据的开头。
不应该是[first,last)里的任一元素。
Return value
An iterator to the end of the destination range where elements have been copied.返回一个指向目标范围最后一个元素的迭代器。
Example
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Edit & Run
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Output:
myvector contains: 10 20 30 40 50 60 70 |
Complexity
Linear in the distance between first and last: Performs an assignment operation for each element in the range.Data races
The objects in the range[first,last) are accessed (each object is accessed exactly once).The objects in the range between result and the returned value are modified (each object is modified exactly once).
result以及返回值之间的所有元素都将会被修改。
Exceptions
Throws if either an element assignment or an operation on iterators throws.Note that invalid arguments cause undefined behavior.
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//写的错误或者不好的地方请多多指导，可以在下面留言或者点击左上方邮件地址给我发邮件，指出我的错误以及不足，以便我修改，更好的分享给大家，谢谢。
转载请注明出处：http://blog.csdn.net/qq844352155
author:天下无双
Email:[email protected]
2014-9-8
于GDUT
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