[LeetCode]4Sum

class Solution {
//fix i, j, then let p q walk to find out the fourSum target O(n^3)
//there exists O(n^2logn) solution
public:
	vector<vector<int> > fourSum(vector<int> &num, int target) {
		// Start typing your C/C++ solution below
		// DO NOT write int main() function
		if(num.size() < 4) return vector<vector<int> >();
		sort(num.begin(), num.end());
		vector<vector<int>> ans;
		for (int i = 0; i < num.size()-3; ++i)
		{
			for (int j = i+1; j < num.size()-2; ++j)
			{
				int p = j+1; int q = num.size()-1;
				fourSum_aux(num, target, i, j, p, q, ans);
			}
		}
		return ans;
	}

	void fourSum_aux( const vector<int> & num, int target, int i, int j, int p, int q, 
					  vector<vector<int>>& ans ) 
	{
		//throw std::exception("The method or operation is not implemented.");
		target = target-num[i]-num[j];
		while (p < q)
		{
			int sum = num[p]+num[q];
			if(sum > target)
				q--;
			else if (sum < target)
				p++;
			else 
			{
				vector<int> path(4);
				path[0] = num[i]; path[1] = num[j]; path[2] = num[p]; path[3] = num[q];
				p++;
				if ( find(ans.begin(), ans.end(), path) == ans.end() )//...
					ans.push_back(path);
			}
		}
	}


};
second time
class Solution {
public:
    void fourSumUtil(vector<int>& num, int target, int firstIdx, int secondIdx, vector<vector<int> >& allPath)
    {
        target = target-num[firstIdx]-num[secondIdx];
        int left = secondIdx+1;
        int right = num.size()-1;
        while(left < right)
        {
            int sum = num[left]+num[right];
            if(sum < target) left++;
            else if(sum > target) right--;
            else
            {
                vector<int> path(4);
                path[0] = num[firstIdx]; path[1] = num[secondIdx]; path[2] = num[left]; path[3] = num[right];
                allPath.push_back(path);
                left++;
            }
        }
    }
    vector<vector<int> > fourSum(vector<int> &num, int target) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        sort(num.begin(), num.end());
        vector<vector<int> > allPaths;
        for(int i = 0; i < (int)num.size()-3; ++i)
        {
            for(int j = i+1; j < (int)num.size()-2; ++j)
            {
                fourSumUtil(num, target, i, j, allPaths);
            }
        }
        //abort duplicates
        vector<vector<int> > ans;
        for(int i = 0; i < allPaths.size(); ++i)
            if(find(ans.begin(), ans.end(), allPaths[i]) == ans.end()) ans.push_back(allPaths[i]);

        return ans;
    }
};

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