PHP实现JavaScript的escape和unescape

function.php

1. function   escape($str){ 
2.         preg_match_all( "/[/x80-/xff].|[/x01-/x7f]+/ ",$str,$newstr); 
3.         $ar   =   $newstr[0]; 
4.         foreach($ar   as   $k=> $v){ 
5.                 if(ord($ar[$k])> =127){ 
6.                         $tmpString=bin2hex(iconv( "GBK ", "ucs-2 ",$v)); 
7.                         if   (!eregi( "WIN ",PHP_OS)){ 
8.                                 $tmpString   =   substr($tmpString,2,2).substr($tmpString,0,2); 
9.                         } 
10.                         $reString.= "%u ".$tmpString; 
11.                 }   else   { 
12.                         $reString.=   rawurlencode($v); 
13.                 } 
14.         } 
15.         return   $reString; 
16. } 
19. function   unescape($str)   { 
20.     $str   =   rawurldecode($str); 
21.     preg_match_all( "/(?:%u.{4})|&#x.{4};|&#/d+;|.+/U ",$str,$r); 
22.     $ar   =   $r[0]; 
23.     foreach($ar   as   $k=> $v)   { 
24.         if(substr($v,0,2)   ==   "%u "){ 
25. if   (!eregi( "WIN ",PHP_OS)){ 
26. $tmpString   =   "%u ".substr($v,4,2).substr($v,2,2); 
27. } 
28.             $ar[$k]   =   iconv( "UCS-2 ", "GB2312 ",pack( "H4 ",substr($tmpString,-4))); 
29.   } 
30.         elseif(substr($v,0,3)   ==   "&#x ") 
31.             $ar[$k]   =   iconv( "UCS-2 ", "GB2312 ",pack( "H4 ",substr($v,3,-1))); 
32.         elseif(substr($v,0,2)   ==   "&# ")   { 
33.             $ar[$k]   =   iconv( "UCS-2 ", "GB2312 ",pack( "n ",substr($v,2,-1))); 
34.         } 
35.     } 
36.     return   join( " ",$ar); 
37. } 

 

document.write(unescape('<?php echo escape('测试，看看吧！');?>'));

 

ELSE

  function   escape($str)   {  
      preg_match_all("/[/x80-/xff].|[/x01-/x7f]+/",$str,$r);  
      $ar   =   $r[0];  
      foreach($ar   as   $k=>$v)   {  
  if(ord($v[0])   <   128)  
      $ar[$k]   =   rawurlencode($v);  
  else  
      $ar[$k]   =   "%u".bin2hex(iconv("BIG5","UCS-2",$v));  
      }  
      return   join("",$ar);  
  }   
   
  alert(unescape('$str'));

 

Else: http://topic.csdn.net/u/20080928/10/cde07c2d-5b07-4d98-8dfa-eb6ee7e28bad.html