OpenCV 求外接矩形以及旋转角度

 

OpenCV 求外接矩形以及旋转角度_第1张图片

 

 

程序没有写完整,大概功能就是实现了,希望大家分享学习,把他改对

 

// FindRotation-angle.cpp : 定义控制台应用程序的入口点。
//

// findContours.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"



#include <iostream>
#include <vector>
#include <opencv2/opencv.hpp> 
#include <opencv2/core/core.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <opencv2/highgui/highgui.hpp>


#pragma comment(lib,"opencv_core2410d.lib")      
#pragma comment(lib,"opencv_highgui2410d.lib")      
#pragma comment(lib,"opencv_imgproc2410d.lib") 

#define PI 3.1415926

int main()
{
	// Read input binary image

	char *image_name = "test2.jpg";
	cv::Mat image = cv::imread(image_name,0);
	if (!image.data)
		return 0; 

	cv::namedWindow("Binary Image");
	cv::imshow("Binary Image",image);


	
	// 从文件中加载原图  
	   IplImage *pSrcImage = cvLoadImage(image_name, CV_LOAD_IMAGE_UNCHANGED);  
	  
		   // 转为2值图
		
	 cvThreshold(pSrcImage,pSrcImage,200,255,cv::THRESH_BINARY_INV);
		   
	
	   image = cv::Mat(pSrcImage,true);

	   cv::imwrite("binary.jpg",image);

	// Get the contours of the connected components
	std::vector<std::vector<cv::Point>> contours;
	cv::findContours(image, 
		contours, // a vector of contours 
		CV_RETR_EXTERNAL, // retrieve the external contours
		CV_CHAIN_APPROX_NONE); // retrieve all pixels of each contours

	// Print contours' length
	std::cout << "Contours: " << contours.size() << std::endl;
	std::vector<std::vector<cv::Point>>::const_iterator itContours= contours.begin();
	for ( ; itContours!=contours.end(); ++itContours) 
	{

		std::cout << "Size: " << itContours->size() << std::endl;
	}

	// draw black contours on white image
	cv::Mat result(image.size(),CV_8U,cv::Scalar(255));
	cv::drawContours(result,contours,
		-1, // draw all contours
		cv::Scalar(0), // in black
		2); // with a thickness of 2

	cv::namedWindow("Contours");
	cv::imshow("Contours",result);






	// Eliminate too short or too long contours
	int cmin= 100;  // minimum contour length
	int cmax= 1000; // maximum contour length
	std::vector<std::vector<cv::Point>>::const_iterator itc= contours.begin();
	while (itc!=contours.end()) {

		if (itc->size() < cmin || itc->size() > cmax)
			itc= contours.erase(itc);
		else 
			++itc;
	}

	// draw contours on the original image
	cv::Mat original= cv::imread(image_name);
	cv::drawContours(original,contours,
		-1, // draw all contours
		cv::Scalar(255,255,0), // in white
		2); // with a thickness of 2

	cv::namedWindow("Contours on original");
	cv::imshow("Contours on original",original);

	

	// Let's now draw black contours on white image
	result.setTo(cv::Scalar(255));
	cv::drawContours(result,contours,
		-1, // draw all contours
		cv::Scalar(0), // in black
		1); // with a thickness of 1
	image= cv::imread("binary.jpg",0);

	// testing the bounding box 
	


	

	std::vector<std::vector<cv::Point>>::const_iterator itc_rec= contours.begin();
	while (itc_rec!=contours.end())
	{
		cv::Rect r0= cv::boundingRect(cv::Mat(*(itc_rec)));
		cv::rectangle(result,r0,cv::Scalar(0),2);
			++itc_rec;
	}

	

	cv::namedWindow("Some Shape descriptors");
	cv::imshow("Some Shape descriptors",result);


	CvBox2D     End_Rage2D;

	CvMemStorage *storage = cvCreateMemStorage(0);  //开辟内存空间


	CvSeq*      contour = NULL;     //CvSeq类型 存放检测到的图像轮廓边缘所有的像素值,坐标值特征的结构体以链表形式

	cvFindContours( pSrcImage, storage, &contour, sizeof(CvContour),CV_RETR_CCOMP, CV_CHAIN_APPROX_NONE);//这函数可选参数还有不少



	for(; contour; contour = contour->h_next)   //如果contour不为空,表示找到一个以上轮廓,这样写法只显示一个轮廓
		//如改为for(; contour; contour = contour->h_next) 就可以同时显示多个轮廓
	{  

		End_Rage2D = cvMinAreaRect2(contour);    //代入cvMinAreaRect2这个函数得到最小包围矩形  这里已得出被测物体的角度,宽度,高度,和中点坐标点存放在CvBox2D类型的结构体中,主要工作基本结束。
	
	std::cout <<" angle:\n"<<(float)End_Rage2D.angle << std::endl;      //被测物体旋转角度 
	
	}
	cv::waitKey();
	return 0;


}


 

 

 

 

 

重新写了一下这个代码,还是稍微有点小问题,希望大家共同探讨:

 

http://blog.csdn.net/wangyaninglm/article/details/43959947

 

 

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