gfx.DrawLine(new Pen(Color.Blue, 1), x + 10, x, x + 20, y);
Graphics gfx = e.Graphics;
int x = 150;
int y = 8380000;
gfx.DrawLine(new Pen(Color.Red, 1), x, x, x + 10, y);
x = 150;
y = 8388608 +1;
gfx.DrawLine(new Pen(Color.Blue, 1), x + 10, x, x + 20, y);
发现坐标值太大时,发生反方向,什么原因??
我们发现 8388608是Graphic的ClipBound的宽度和高度
My first thought is that as y is really way off the actual bitmap bounds you are pushing the limits too far here. Actually I gave a look at gfx.ClipBounds.Top and found this is 8388608/2. So it's likely your very high y value is truncated in a way that gives either a negative value sligthly above gfx.ClipBounds.Bottom or a positive value slightly below gfx.ClipBounds.Top.
You have (or had ?) something similar in DirectX that is you could use coordinates way off the actual size of a render target but you still had a high value limit (I believe that if you goes past this value, it fails).
So just try to avoid using way off values when it's easy to do otherwise (or check against ClipBounds if you can't do otherwise)...