uva 230 Borrowers 习题5-8 (STL string,map练习)

题目:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=166


参考博客:http://blog.csdn.net/wcr1996/article/details/40898767  感谢wcr1996的分享,刚开始连题意都没搞清,模仿着写的,感谢!


说明:练习了find()方法,substr()的用法,map的用法,收货颇多的。


#include<stdio.h>
#include<iostream>
#include<map>
#include<string>
#include<vector>
#include<algorithm>
using namespace std;

struct book{
    string author;
    int status;
}y;

map<string,book> books;
vector<string>bname;

bool cmp(string a,string b){
    if(books[a].author!=books[b].author) return books[a].author<books[b].author;
    return a<b;
}

int main(){
    string x,z,m;
    while(getline(cin,m)){
        if(m=="END") break;

        int pst=m.find('"');
        int pend=m.find_last_of("\"");
        x=m.substr(pst,pend+1);//x字符串为书名(包括"")  例如"The Canterbury Tales"
        bname.push_back(x);

        pst=m.find("by")+3;
        y.author=m.substr(pst);
        y.status=1;

        books[x]=y;
    }
    sort(bname.begin(),bname.end(),cmp);
    /*for(int i=0;i<bname.size();i++)
        cout<<bname[i]<<endl;*/
    while(cin >>m){
        if(m=="END") break;
        if(m=="BORROW"){
            getchar();
            getline(cin,x);
            books[x].status=0;
        }else if(m=="RETURN"){
            getchar();
            getline(cin,x);
            books[x].status=-1;
        }else if(m=="SHELVE"){
            for(int i=0;i<bname.size();i++)
                if(books[bname[i]].status==-1){
                    int j;
                    for(j=i-1;j>=0;j--)
                        if(books[bname[j]].status==1) break;

                    if(j==-1)//书架没有书,不包括归还的书
                        cout << "Put "<<bname[i]<<" first"<<endl;
                    else
                        cout << "Put "<<bname[i] <<" after "<<bname[j]<<endl;

                    books[bname[i]].status=1;
                }

            cout <<"END"<<endl;
        }
    }
    return 0;
}


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