HDU-1064-Financial Management(水题测试......真无双-大水果)

Financial Management

Time Limit: 400/200 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10333    Accepted Submission(s): 6400

Problem Description

Larry graduated this year and finally has a job. He’s making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what’s been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

 

Input

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

 

Output

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

 

Sample Input

   
   
   
   

    
    
    
    100.00 
489.12 
12454.12 
1234.10 
823.05 
109.20 
5.27 
1542.25 
839.18 
83.99 
1295.01 
1.75
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    $1581.42
   
   
   
   

 

Source

Mid-Atlantic USA 2001

 

Recommend

PrincetonBoy   |   We have carefully selected several similar problems for you:   1076  1070  1056  1090  1062 

好久没来做题了，今天回家测试一下......来一个大大的水题!顺便好好翻译一下......（求平均数）

题目翻译：
劳瑞在今年毕业的最后得到了一个工作，赚了很多钱，但是无论怎么看都不够。（谁会觉得钱够？）劳瑞决定抓住他整体的财政并且解决他的经济问题。这个第一步就是弄清楚他的钱去哪里了。劳瑞有他自己的银行账户，并且想要看他自己有多少钱。通过写一个程序获取他过去每12个月的经济，并计算他们的平均值。

输入：
输入将有12行，每一行都是劳瑞每个月的银行经济值。每个数字都是精确的并且以便士的形式表现出来。并不是美元。

输出：
这个输出将只有一个数字，就是他12个月的平均经济,它将最接近分钱（就是保留两位小数）。是在美元注册之前。并且在最后一行没有空格或者其他字符！

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
    double a,sum=0;
    for(int i=0;i<12;i++)
    {
        scanf("%lf",&a);
        sum+=a;
    }
    printf("$%.2lf\n",sum/12);
    return 0;
}