题目链接:Codeforces 416C Booking System
题目大意:餐馆有n批客人,每批客人给出人数和消费金额。然后餐馆有m个桌子,给出每个桌子可以坐的人数。问说在这一时刻,餐馆可以最大盈利多少,并且接待尽量多的客人。
解题思路:将客人按照消费金额、人数排序,然后桌子按照从小到大排序。消费高的客人尽量找最小满足的桌子给他们。注意输出的时候客人有序号,桌子同样有序号,不能打乱。
#include <stdio.h> #include <string.h> #include <algorithm> using namespace std; const int N = 1005; struct state { int id, val, sum; state () { } }g[N], t[N]; int n, m, v[N]; bool cmpS (const state& a, const state& b) { if (a.val != b.val) return a.val > b.val; return a.sum > b.sum; } bool cmpT (const state& a, const state& b) { return a.sum < b.sum; } void init () { memset(v, 0, sizeof(v)); scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d%d", &g[i].sum, &g[i].val); g[i].id = i; } scanf("%d", &m); for (int i = 0; i < m; i++) { scanf("%d", &t[i].sum); t[i].id = i; } sort(g, g + n, cmpS); sort(t, t + m, cmpT); } void solve () { int ans = 0, cnt = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { if (g[i].sum <= t[j].sum) { cnt++; ans += g[i].val; v[g[i].id] = t[j].id + 1; t[j].sum = 0;; break; } } } printf("%d %d\n", cnt, ans); for (int i = 0; i < n; i++) { if (v[i]) printf("%d %d\n", i + 1, v[i]); } } int main () { init (); solve (); return 0; }