杭电2052 Picture

不要忘了空格

代码如下

#include<stdio.h>
int main()
{
   int i,j,m,n;
   while(~scanf("%d%d",&n,&m))
   {
       for(i=0;i<m+2;i++)
       {
           for(j=0;j<n+2;j++)
           {
               if((i==0&&j==0)||(i==m+1&&j==0)||(i==0&&j==n+1)||(i==m+1&&j==n+1))
                    printf("+");
                else if(j>0&&j<n+1&&((i==0)||(i==m+1)))
                    printf("-");
                else if(j==0&&i>0&&i<m+1)
                    printf("|");
                    else if(j==n+1&&i>0&&i<m+1)
                        printf("|");
                    else
                        printf(" ");
           }
           printf("\n");
       }


       printf("\n");
   }
    return 0;
}

Picture

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 22830    Accepted Submission(s): 11626


Problem Description
Give you the width and height of the rectangle,darw it.
 

Input
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.
 

Output
For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.
 

Sample Input
   
   
   
   
3 2
 

Sample Output
   
   
   
   
+---+ | | | | +---+
 


你可能感兴趣的:(杭电)