C++中abort和exit的区别
abort会发送SIGABORT信号
调用exit后，程序会调用静态对象和全局对象的析构函数，但abor什么析构函数都不会调用。
程序完全退出时，系统会释放所有未释放的内存和和其他资源
abort sends a SIGABRT signal, exit just closes the application performing normal cleanup.
You can handle an abort signal however you want, but the default behavior is to close the application as well with an error code.
abort will not perform object destruction of your static and global members, but exit will.
Of course though when the application is completely closed the operating system will free up any unfreed memory and other resources.
In both abort and exit program termination (assuming you didn't override the default behavior), the return code will be returned to the parent process that started your application.
See the following example:
SomeClassType someobject; void myProgramIsTerminating1(void) { cout<<"exit function 1"<<endl; } void myProgramIsTerminating2(void) { cout<<"exit function 2"<<endl; } int main(int argc, char**argv) { atexit (myProgramIsTerminating1); atexit (myProgramIsTerminating2); //abort(); return 0; }Comments:
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If abort is uncommented: nothing is printed and the destructor of someobject will not be called.
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If abort is commented like above: someobject destructor will be called you will get the following output:
exit function 2
exit function 1